42.6℅ of 230
=(426/10)℅ of 230
=(426×230)/1000
=97980/1000
=97.980
=97.98
Part A:
To determine the values of the times to which the height of the two cannon balls are the same, we equate the given functions.
H(t) = g(t)
Substitute the expressions for each.
-16t² + 48t + 12 = 10 + 15.2t
Transpose all the terms to the left-hand side of the equation.
-16t² + (48 - 15.2)t + (12 - 10) = 0
Simplifying,
-16t² + 32.8t + 2 = 0
The values of t from the equation are 2.11 seconds and -0.059 seconds
Part B:
In the context of the problem, only 2.11 seconds is acceptable. This is because the second value of t which is equal to -0.059 seconds is not possible since there is no negative value for time.
The answer is -1. This is because you can plug in the negative values to see which ones work.
Answer:
14 (insert less than or equal symbol)8x+6
Hope this helps! i hope the symbol is right!
I'll solve 1,2, 8, and 9 and then you can use those techniques to solve the rest.
For 1, we subtract 9 from both sides to separate the 3f and get 3f<12. Dividing both sides by 3, we get f<4
For 2, we add 3 to both sides to get 4n ≥ 108 and dividing by 4 we get n ≥ 27
For 8, we can start off by expanding using the distributive property, getting 12c-15-2c >0. Next, we get 10c-15>0 and adding 15 to both sides we get 10c> 15. After that, we divide both sides by 10 to get c > 15/10 = c> 1.5
For 9, we expand again to get 15j-45+3j < 45. Next, we add 45 to both sides and add from there, getting 18j < 90. Next, we divide both sides by 18 to get j < 5