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sertanlavr [38]
3 years ago
13

Choose all true statements:

Mathematics
2 answers:
leva [86]3 years ago
8 0
<span>1 - All real numbers are rational numbers.   FALSE
All real numbers are NOT rational numbers. The real numbers are made up of rational numbers and irrational numbers.

2 - Some rational numbers are natural numbers. TRUE
All natural number are rational numbers but not all rational numbers are natural numbers. Thus, some rational numbers are natural numbers.

3 - No real numbers are irrational numbers. FALSE
</span><span>The real numbers are made up of rational numbers and irrational numbers. Thus, some real numbers are natural numbers.

4 - All whole numbers are integers. TRUE
The whole numbers are the natural numbers plus 0. The integers comprises of the whole numbers plus the negative of the whole numbers.
Thus, all whole numbers are integers.

5 - Some integers are natural numbers. TRUE
</span>The integers comprises of the whole numbers plus the negative of the whole numbers. <span><span>The whole numbers are the natural numbers plus 0. The natural numbers are the counting numbers, i.e. 1, 2, 3, . . . which are also part of integers.
Thus, some integers are natural numbers.

</span>6 - No rational numbers are integers. FALSE
The rational numbers are made up of the integers and any number that can be expressed as a fraction.</span>
Thus, all integers are rational numbers and some rational numbers are integers.
Andrews [41]3 years ago
3 0

Answer:from top to bottom they go in this order.

2,4,5.

Step-by-step explanation:

got it right in e2020

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12 more than the number 5 and a x
siniylev [52]

Answer:

Step-by-step explanation:

(5+x)+12

4 0
3 years ago
What’s this help pls
lys-0071 [83]

How to solve your problem

9−4+3

9x−4+3x9x-4+3x9x−4+3x

Simplify

1

Combine like terms

9−4+3

9x−4+3x{\color{#c92786}{9x}}-4+{\color{#c92786}{3x}}9x−4+3x

12−4

12x−4{\color{#c92786}{12x}}-412x−4

Solution

12−4

SO D

7 0
2 years ago
Read 2 more answers
A) Write the sequence of natural numbers which are multiplied by 3 ?
Volgvan

Answer:

a) 3, 6, 9, 12, 15,...,3\cdot n, b) 4, 7, 10, 13, 16,...,3\cdot n +1, c) Both sequences are arithmetic.

Step-by-step explanation:

a) The sequence of natural numbers which are multiplied by 3 are represented by the function f(n) = 3\cdot n, n\in \mathbb{N}. Let see the first five elements of the sequence: 3, 6, 9, 12, 15,...

b) The sequence of natural numbers which are multiplied by 3 and added to 1 is represented by the function f(n) = 3\cdot n + 1, n\in \mathbb{N}. Let see the first five elements of the sequence: 4, 7, 10, 13, 16,...

c) Both sequences since differences between consecutive elements is constant. Let prove this statement:

(i) f(n) = 3\cdot n

\Delta f = f(n+1) -f(n)

\Delta f = 3\cdot (n+1) -3\cdot n

\Delta f = 3

(ii) f(n) = 3\cdot n +1

\Delta f = f(n+1)-f(n)

\Delta f = [3\cdot (n+1)+1]-(3\cdot n+1)

\Delta f = 3

Both sequences are arithmetic.

8 0
2 years ago
Which of the following is graphed below?
nikklg [1K]
The function that is graphed is...
B.) y = |x - 3| - 4 

Since the lines "|" in the function make it a V shape. 
And when you graph the one point where the the 2 lines meet it is.
(-3, -4) 

So this answer is correct. :P

Good Luck! :)
5 0
3 years ago
Read 2 more answers
HELP ME PLSSS OMG OMG PLS THIS IS A BIG LART OF MY GRADE ON A TWST AND I RLLY RLLY NEED IT PLE HELP
Elza [17]

Answer: The answer is B.

6 0
2 years ago
Read 2 more answers
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