the length of a rectagle is 5 in longer than its width. if the perimeter of the rectangle is 56 in, find its length and width
1 answer:
Answer:
Step-by-step explanation:
Let the width of the rectangle = x
As length is 5 inches longer than width, we have to add 5 to width
Length = x + 5
Perimeter of ractangle = 56 in
2* (length + width) = 56
2*( x + 5 + x) = 56
2* (2x + 5) = 56
Use distributive property: a*(b +c) =(a*b) + (a * c)
2*2x + 2*5 = 56
4x + 10 = 56
Subtract 10 from both sides
4x = 56- 10
4x = 46
Divide both sides by 4
x = 46/4
x = 11.5
Width = 11.5 in
length = 11.5 + 5
= 16.5 in
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