<span>In this equation, 36>11 and so the ellipse has major axis along x axis
standard equation of ellipse with major axis is along x axis
x^2/a^2+y^2/b^2=1,
the foci are at (ae,0) and (–ae,0)
eccentricity e is given by
ae=√(a^2-b^2)
In this case ae=√(36-11)= √25=+/- 5
Focii are(-5,0) and(5,0) </span>
Answer:
i have no idea
Step-by-step explanation:
Answer:
The requires solution to the given differential equation is
y = (1/2)ln(x² - 10x + 50)
Step-by-step explanation:
The workings are shown in the attachment.
Answer:
the 1.5 goes between -1 and 0 and -3/2 too and -4/3 between the-2 and the 3/2 between the 0 and 1
Step-by-step explanation: