Answer:
The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.
Step-by-step explanation:
Let the cost of 1 pound of meat be x
Let the cost of 1 pound of cheese be y
Cost of 4 pounds of meat = 4x
Cost of 5 pounds of cheese = 5y
Since we are given that one customer purchases 4 pounds of meat and 5 pounds of cheese for a total of $30.50.
So, equation becomes :
Cost of 11 pounds of meat = 11x
Cost of 14 pounds of cheese = 14y
Since we are given that a sandwich shop owner comes in and purchases 11 pounds of meat and 14 pounds of cheese for $84.50.
So, equation becomes :
Thus the system of equations are :
-1 (Red line)
-2 (Black line)
Solving these equations graphically we get the solution
x = $4.5
y = $2.5
Hence The cost of 1 pound meat is $ 4.5 And cost of 1 pound of cheese is $ 2.5.
Answer: Dear friend my answer for this question is 86.
Step-by-step explanation:Let the two digits of two digit number be, 10s digit x and 1s digit y.
x + y = 14
x = 14 - y…..Eq..1
The nuber formed is 10x + y
If the number formed by reversing the digits is 18 less than the original number, what is the original number
On reversing the digit the number will be 10y + x
10y + x + 18 = (10x + y)
10y + x = 10x + y - 18
10y - y + x - 10x = - 18
9y - 9x = -18…Eq..2
Now substituting the value of x from Eq..1 to Eq..2
9y - 9 (14 - y) = - 18
9y - 126 + 9y = - 18
18y = 126 - 18
18y = 108
y = 108/18
y = 6
Thus 1s digit if the number is 6
Substituting the derived value of y in Eq..1 to derive value of x.
x = 14 - y
x = 14 - 6
x = 8
The 10s digit if two digit number is 8.
The original number formed is 86.
On reversing the digits, the number transform to 68, which is 18 less than original number
Answer the original number is 86.
The answer should be 62 °
180°-118°=62°
Subtract 118° from 180° because a parallel line is 180°. So you just have to find the other side of the line.
Hope this helps.
Answer:
(-4, 2)
Step-by-step explanation:
4x+2y=-12
3x+y=-10
Start by dividing the first equation by 2 to simplify it...
2x+y=-6
Then, subtract -2x from both sides to isolate y...
y=-2x-6
Substitute -2x-6 for y in the second equation...
3x-2x-6=-10
Combine like terms...
x-6=-10
Add 6 to both sides
x-6+6=-10+6
x=-4
Plug -4 in for x to solve for y:
3(-4)+y=-10
-12+y=-10
Add 12 to both sides
-12+12+y=-10+12
y=2
(x,y)=(-4,2)
Answer:
the upper left Quadrant is Quadrant II
