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3 years ago

A $22,000 car depreciates by 12% per year.

1 answer:

5 0

$22,000 * 0.12 = $2,640
so
$22,000 - $2,640 = $19,360
so
$19,360 after 1 year.

$19,360 * 0.12 = $2,323.20
$19,360 - $2,323.20 = $17,036.80 (2 years)

$17,036.80 * 0.12 = $2,044.416
Don't round until you finish the problem.
$17,036.80 - $2.044.416 = $14,992.384 (3 years)

$14,992.384 * 0.12 = $1,799.08608
$14,992.384 - $1,799.08608 = $13,193.29792 (4 years)
ROUND
$13,193.29792 rounded to $13,193.30

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If f(x) = (x + 9 and g(x) = --6, which describes the range of (f + g)(x)?

S_A_V [24]

Given:

Consider the below figure attached with this question.

To find:

The value of $(f+g)(x)$ .

Solution:

The given functions are:

$f(x)=|x|+9$

$g(x)=-6$

Now,

$(f+g)(x)=f(x)+g(x)$

$(f+g)(x)=|x|+9+(-6)$

$(f+g)(x)=|x|+9-6$

$(f+g)(x)=|x|+3$

We know that,

$|x|\geq 0$

Adding 3 on both sides, we get

$|x|+3\geq 0+3$

$(f+g)(x)\geq 3$

So, $(f+g)(x)\geq 3$ for all values of x.

Hence, the correct option is A.

6 0

3 years ago

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

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