Question

In humans curly hair (C) is dominant to straight hair (c), and freckles (F) is dominant to not having freckles. A man heterozygous for curly hair and who has no freckles marries a woman with straight hair and who is heterozygous for freckles. What is the probability of having a child with this genotype: CcFf

Answer 1

Answer:

Probability of having a child with this genotype: CcFf is $\frac{1}{4}$

Explanation:

Given -

Curly hair (C) is dominant to straight hair (c)

and

Freckles (F) is dominant to not having freckles (f)

Genotype of  man heterozygous for curly hair and no freckles  is Ccff

Genotype of  woman with straight hair and  heterozygous condition for freckles is ccFf

The cross is between Ccff and  ccFf

The following offspring would be produced

Ccff and  ccFf

Cf       Cf         cf     cf

cF CcFf CcFf ccFf    ccFf

cF CcFf CcFf ccFf     ccFf

cf Ccff         Ccff         ccff      ccff

cf Ccff         Ccff         ccff       ccff

Genotype –  

CcFf – 4 in number  

ccFf - 4 in number

Ccff - 4 in number

ccff  - 4 in number

Phenotype  

CcFf – heterozygous for both the curly hairs and freckles

ccFf – straight hairs with heterozygous freckle condition

Ccff – Heterozygous curly hair with no freckles

ccff – staright hairs with no freckels

probability of having a child with this genotype: CcFf is

$\frac{4}{16} \\\frac{1}{4}$