Since the area of the poster doesn't change by putting it in a frame, we presume the question is asking what the area of the framed poster is.
The length of the poster in its frame is ...
(frame width on one side) + (poster length) + (frame width on the other side)
2 in + 32 in + 2 in = 36 in
Likewise, the width of the poster in its frame is ...
2 in + 24 in + 2 in = 28 in
The area of a rectangle 36 in by 28 in is the product of these dimensions:
Area = (36 in)×(28 in) = (36×28) in² = 1008 in²
Answer:
53 marks
Step-by-step explanation:
To sue a linear equation to solve the given problem, we must assign a function to the score of one of them. Let the score of Azmah be N. Then given that Azmah scored 17 marks more than Yazid, Yazid's score will be
= N - 17
Given that Suzana's score is twice of Yazid's score, then Suzana's score
= 2(N - 17)
If their total score is 161 then
N + N - 17 + 2(N - 17) = 161
4N = 161 + 51
4N = 212
N = 53 . This is Azmah's score
Answer
it could be 73/x
Step-by-step explanation:
Answer: 6x - 3 over x^3
Step-by-step explanation:
Answer:
8,-8
Step-by-step explanation:
