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inna [77]
3 years ago
10

GIVING BRAINLIST TO THE CORRECT ANSWER PLS ANSWER!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
docker41 [41]3 years ago
7 0

Answer:

a = -1/2 & k = 3/7

Step-by-step explanation:

Solve for a over the real numbers:

24 a^3 + 8 a^2 + 6 a + 4 = 0

The left hand side factors into a product with three terms:

2 (2 a + 1) (6 a^2 - a + 2) = 0

Divide both sides by 2:

(2 a + 1) (6 a^2 - a + 2) = 0

Split into two equations:

2 a + 1 = 0 or 6 a^2 - a + 2 = 0

Subtract 1 from both sides:

2 a = -1 or 6 a^2 - a + 2 = 0

Divide both sides by 2:

a = -1/2 or 6 a^2 - a + 2 = 0

Divide both sides by 6:

a = -1/2 or a^2 - a/6 + 1/3 = 0

Subtract 1/3 from both sides:

a = -1/2 or a^2 - a/6 = -1/3

Add 1/144 to both sides:

a = -1/2 or a^2 - a/6 + 1/144 = -47/144

Write the left hand side as a square:

a = -1/2 or (a - 1/12)^2 = -47/144

(a - 1/12)^2 = -47/144 has no solution since for all a on the real line, (a - 1/12)^2 >=0 and -47/144<0:

Answer: a = -1/2

______________________________________

Solve for k over the real numbers:

(7 k - 3) (k^2 - 2 k + 7) = 0

Split into two equations:

7 k - 3 = 0 or k^2 - 2 k + 7 = 0

Add 3 to both sides:

7 k = 3 or k^2 - 2 k + 7 = 0

Divide both sides by 7:

k = 3/7 or k^2 - 2 k + 7 = 0

Subtract 7 from both sides:

k = 3/7 or k^2 - 2 k = -7

Add 1 to both sides:

k = 3/7 or k^2 - 2 k + 1 = -6

Write the left hand side as a square:

k = 3/7 or (k - 1)^2 = -6

(k - 1)^2 = -6 has no solution since for all k on the real line, (k - 1)^2 >=0 and -6<0:

Answer: k = 3/7

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