Answer:
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Step-by-step explanation:
Given;
Standard deviation r= 25mg
Width of confidence interval w= 10mg
Confidence interval of 95%
Margin of error E = w/2 = 10mg/2 = 5mg
Z at 95% = 1.96
Margin of error E = Z(r/√n)
n = (Z×r/E)^2
n = (1.96 × 25/5)^2
n = (9.8)^2
n = 96.04
n > 96
Therefore, the number of samples should be more than 96 for the width of their confidence interval to be no more than 10mg
Answer:
its B
Step-by-step explanation:
The difference between the rate of change of B and the rate of change of A is 15.
<h3>
How to get the difference in the rates of change?</h3>
First, we need to get the two rates of change.
We have two linear functions.
A: y = 35*x
For function A the rate of change is the slope, wich is 35.
Function B is graphed.
Remember that if a line passes through two points (x₁, y₁) and (x₂,y₂) then the slope is:
In the graph, we can see that line B passes through (0, 0) and (1, 50), then the slope is:
Then the rate of change of B is 50.
The difference between the rates of change is:
diff = 50 - 35 = 15
If you want to learn more about rates of change:
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Answer: w= -4
Step-by-step explanation:
7w-180=52w
Subtract 7w on both sides.
-180=45w
Divide both sides by 45.
-4=w
The distribution shaped for which the mean and median must be about the same will be:
D. Symmetric
E. uniform
<h3>How to illustrate the information?</h3>
In a symmetric distribution, the median is equal to the mean. The bell-shaped distribution is same as the standard normal distribution.
In a right-skewed distribution, the median is much less than the mean and a bimodal distribution is one with two modes.
Therefore, the correct options are D and E.
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