Answer:
Increase in population and desire to search for land
Answer:
5.71 x 10^13 C.
Explanation:
We are given the following parameters or data or information and these data are going to help us in solving this particular Question or problem effectively and efficiently;
=> mass of Earth = 5.98 × 10^ 24kg, mass of Moon = 7.35 × 10^22 kg and the radius of orbit = 3.84 × 10^8m.
Recall that H =( G × m1 × m2) / r^2. where m1 and m2 are the masses of the two bodies amd r is the radius.
We will be making use of the formula below:
the value of Q to maintain the present orbit = √ { ( 7.35 × 10^22 ) × (5.98 × 10^24) × 4 × π × V.
the value of Q to maintain the present orbit = 5.71 x 10^13 C.
Ask the Principle! the Principle has a map of her/his school for sure. And therefore could tell you the distance around your school.
