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Aliun [14]
3 years ago
15

Can someone help me with question 9

Mathematics
1 answer:
Troyanec [42]3 years ago
8 0

Please refer the pictures below-

Hence the area of the road is 9600m2

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I need the answer and maybe someone can tell me how to do it? Please and Thanks!! :))
UNO [17]

Answer:

83

Step-by-step explanation:

The 126 angle is an exterior angle of the triangle.

The 43 and x angles are the two remote interior angles of the 126 angle.

<em>Theorem:</em>

<em>The measure of an exterior angle of a triangle equals the sum of the measures of the remote interior angles.</em>

x + 43 = 126

x = 83

4 0
4 years ago
Read 2 more answers
7/8m+9/10-2m-3/5<br> Combine like terms to create an equivalent expression.
stich3 [128]

Answer:

-1.123m+0.3

or in fraction form -9/8m+3/10

Step-by-step explanation:

first you subtract 7/8 from 2

then you subtract again 9/10 from 3/5

4 0
3 years ago
Please Answers with steps...will be much appreciated!!!
11Alexandr11 [23.1K]
To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:

 7) (x)=x³-6x²+8x
 (x)=x(x³-6x²+8)
 (x)=(x-4)(x-2)x

 The lenght is: x
 The height is= (x-4)

 8) √(2x+8)-6=4

1. You need to clear the variable "x". Then:

 √(2x+8)=4+6
 √(2x+8)=10
 (√2x+8)²=10²
 2x+8=100
 2x=100-8
 x=92/2
 x=46

 9) l4x+3l=9+2x

 1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:

 2. Negative:

 l4x+3l=9+2x
 -4x-3=9+2x
 -4x-2x=9+3
 -6x=12
 x=12/-6
 x=-2

 3. Positive:

 l4x+3l=9+2x
 4x+3=9+2x
 4x-2x=9-3
 2x=6
 x=6/2
 x=3
4 0
3 years ago
Find the area of a rectangle that has a length of (x - 5) and a width of (3x + 1).
avanturin [10]

Answer:

A=3x^2 -14x -5

Step-by-step explanation:

(x-5)(3x+1)

3x^2 +x -15x -5

3x^2 -14x -5

5 0
3 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9

6 0
1 year ago
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