Ask question

Ask question

All categories

2 years ago

6

according to the graph, what is the approximate average rate of change in the radius of the circle as the area increases from 3

square feet to 7 square feet?

1 answer:

slamgirl [31]2 years ago

7 0

Answer: the answer is 0.125 foot per square foot

Step-by-step explanation:

You might be interested in

Help with formulas and explain

Vlad [161]

A. T. S.A =2* AREA OF TRIANGLE +PREIMETER*5.56

VOLUME=AREA OF *LENGTH[ 5.56]

B. T. S. A=πR{R + SLANT HIGHT }

VOLUME=1/3*π*R*HIGHT{ 7 }

volume of a sphere is 3 by 4 by R cube and surface area of a sphere is 4 Pi R Square

6 0

3 years ago

Find sin 2a and cot 2a:

geniusboy [140]

Answer:

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}$

Step-by-step explanation:

$\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\$

$sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}$

8 0

2 years ago

Which statement correctly describes the slope of the linear function that is represented by the data in the table?

777dan777 [17]

Slope=change in y/change in x

one way is t pick 2 points, (x1,y1) and (x2,y2)
the slope is (y2-y1)/(x2-x1)

pick some points
(8,4) and (8,0)
slope=(0-4)/(8-8)=-4/0=undefined
the slope is undefined
so you could say there is no solpe

answer is D

5 0

2 years ago

Read 2 more answers

What is the domain of the inverse of a relation?

GalinKa [24]

The domain is the space between the end points on the x axis
ex: D:-2(<=)x(<=)4 this means that the domain is any numbers between -2 and 4

4 0

3 years ago

Read 2 more answers

Write a rule for the function

cestrela7 [59]

Answer:-18

Step-by-step explanation: i know evertyhing

3 0

2 years ago