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jekas [21]
3 years ago
10

How do I get help with my math homework ​

Mathematics
2 answers:
rewona [7]3 years ago
8 0
Just ask a question and people will answer them for u
Anna71 [15]3 years ago
6 0

Answer:

Ask the question(s) you need help with, and someone on here will help you out if they can. There should be a "Ask Question" button that will also help to see if any other students have asked the same question. If not, ask for yourself. To ask questions, you need points, and to get points, you help out other students on here.

Hope that answers your question:)

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Find the GCF of the following literal terms xxyyyzz and xxxxzzz
Degger [83]

Answer:

x^2z^2

Step-by-step explanation:

Look atthe factors they have in common.

xxyyyzz and xxxxzzz

GCF = x^2z^2

5 0
4 years ago
Read 2 more answers
Calc AB multiple choice. Please help
Vinvika [58]
You start off with 4*(cos(x+(pi/3)))

Let's place the 4 aside for the time being:

Cos(u+j) = cos(u)*cos(j) - sin(u)*sin(j)

cos(x+(pi/3)) = cos(x)*cos(pi/3) - sin(x)*sin(pi/3)

cos(x+(pi/3)) = cos(x)/2 - (sqrt(3)/2)*sin(x)

Multiplying by the 4 we put aside:

4*cos(x+(pi/3)) = 2*cos(x) - 2*sqrt(3)*sin(x)

The correct answer is B
3 0
3 years ago
Read 2 more answers
Somebody please help me on this!!
miskamm [114]
80 degrees because it decreases by a half each time so by the time it is E (the fourth letter) it has gotten to 20 so the answer is 160
5 0
3 years ago
Read 2 more answers
Which relation is not a function?
BaLLatris [955]

Answer: B repeating domain is 1

Step-by-step explanation: Repeat domain is not a function. Hope this help:)

5 0
2 years ago
Reflect triangle STU across line ST.Which of these is a valid reason why the image of U will coincide with J?
algol [13]

Answer:

The correct option is;

c.

Step-by-step explanation:

The given translation given is that of a reflection across a line ST

Whereby we take the line ST to represent the x-axis, then a reflection across ST will be of the form;

Coordinates of point of primage before reflection = (x, y)

Coordinates of point of image after reflection = (x, -y)

Therefore, the coordinates of the point of the reflected image of U will be the same as the coordinate of the point J and the image of U coincides with the point J

Therefore, the image of U and J are the same distance along the same ray from the T.

5 0
3 years ago
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