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Annette [7]
3 years ago
9

Add. (−x3+26x2−7x−13)+(6x4−x3+8x+27) Express the answer in standard form. Enter your answer in the box.

Mathematics
2 answers:
arlik [135]3 years ago
4 0

Answer:=−x3+26x2+−7x+−13+6x4+−x3+8x+27

=(6x4)+(−x3+−x3)+(26x2)+(−7x+8x)+(−13+27)

=6x4+−2x3+26x2+x+14

Answer: =6x4−2x3+26x2+x+14

             


topjm [15]3 years ago
4 0

Answer:

6x^4-2x^3+26x^2+x+14

Step-by-step explanation:

(-x^3+26x^2-7x-13)+(6x^4-x^3+8x+27)

To add both parenthesis we remove the parenthesis first

(-x^3+26x^2-7x-13)+(6x^4-x^3+8x+27)

-x^3+26x^2-7x-13+6x^4-x^3+8x+27

Now combine like terms

-x^3+26x^2-7x-13+6x^4-x^3+8x+27

-2x^3+26x^2+x+14+6x^4

Now write it in standard form with highest exponent first

6x^4-2x^3+26x^2+x+14

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Roger served 5/8 pound of cracker wich was 2/3 of the entire box what was the weight of the crackers originally in the box
horrorfan [7]
Answer:
original weight of the box = 15 / 16 pounds

Explanation:
Assume that the original amount in the box is x.
We are given that:
5/8 pounds represent 2/3 of the total amount (x).
This can be translated into the following equation:
(2/3) x = 5 / 8

Now, we will solve for x as follows:
(2/3) x = 5 / 8
Multiply both sides by 24 to get rid of the denominators as follows:
(2/3) x * 24 = (5 / 8) * 24
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Divide both sides by 16 to isolate the x as follows:
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Hope this helps :)

8 0
4 years ago
What is the missing coefficient?
Afina-wow [57]

For this case we have the following expression:

(15x ^ 2 + 11y ^ 2 + 8x) - (7x ^ 2 + 5y ^ 2 + 2x) =

We eliminate the parentheses taking into account that:

- * + = -\\15x ^ 2 + 11y ^ 2 + 8x-7x ^ 2-5y ^ 2-2x

We add similar terms:

15x ^ 2-7x ^ 2 + 11y ^ 2-5y ^ 2 + 8x-2x =

Different signs are subtracted and the sign of the major is placed:

8x ^ 2 + 6y ^ 2 + 6x

Finally, the expression is reduced to:

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Answer:

8x ^ 2 + 6y ^ 2 + 6x

Option B

6 0
3 years ago
Read 2 more answers
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kobusy [5.1K]
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