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pentagon [3]
3 years ago
8

Roger served 5/8 pound of cracker wich was 2/3 of the entire box what was the weight of the crackers originally in the box

Mathematics
1 answer:
horrorfan [7]3 years ago
8 0
Answer:
original weight of the box = 15 / 16 pounds

Explanation:
Assume that the original amount in the box is x.
We are given that:
5/8 pounds represent 2/3 of the total amount (x).
This can be translated into the following equation:
(2/3) x = 5 / 8

Now, we will solve for x as follows:
(2/3) x = 5 / 8
Multiply both sides by 24 to get rid of the denominators as follows:
(2/3) x * 24 = (5 / 8) * 24
16 x = 15
Divide both sides by 16 to isolate the x as follows:
x = 15 / 16 pounds

Hope this helps :)

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Vinvika [58]

Answer:  x = 0; y = 2; z = 5

Step-by-step explanation:

x+2y+z=9

x-y+3z=13

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==

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(y-2) +2y + 5 = 9

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x+2y+z=9

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x = 0

====

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3 years ago
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iVinArrow [24]

Answer:

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Step-by-step explanation:

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