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3 years ago

Roger served 5/8 pound of cracker wich was 2/3 of the entire box what was the weight of the crackers originally in the box

1 answer:

8 0

Answer:
original weight of the box = 15 / 16 pounds

Explanation:
Assume that the original amount in the box is x.
We are given that:
5/8 pounds represent 2/3 of the total amount (x).
This can be translated into the following equation:
(2/3) x = 5 / 8

Now, we will solve for x as follows:
(2/3) x = 5 / 8
Multiply both sides by 24 to get rid of the denominators as follows:
(2/3) x * 24 = (5 / 8) * 24
16 x = 15
Divide both sides by 16 to isolate the x as follows:
x = 15 / 16 pounds

Hope this helps :)

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32+2/3(21y-6) in factored form

artcher [175]

Answer:

14(y + 2).

Step-by-step explanation:

32 +2/3(21y - 6)

Distributing the 2/3 over the parentheses:

= 32 + 2/3*21y + 2/3 * -6

= 32 + 14y - 4

= 14y + 28

= 14(y + 2).

6 0

3 years ago

Evaluate the expression when y=6 and x = 35.<br> x-3y

vredina [299]

Answer:

Step-by-step explanation:

Given: y = 6; x + 35

Step 1: Equation

x - 3y

Step 2: Substitution

35 - 3(6)

Step 3: Solving

35 - 18 = 17

Answer:

Hope This Helps :)

4 0

3 years ago

Read 2 more answers

For the dinner special at a restaurant, the customer must choose an appetizer, a salad, an entree, a side dish, and a dessert. H

Ostrovityanka [42]

Answer:

The number of possible dinner specials are 4368.

Step-by-step explanation:

The number of dinner specials = 5

They include appetizer, a salad, an entree, a side dish, and a dessert.

Possible items to choose from = 16.

They are 1. Appetizer Chicken strips, 2. Shrimp cocktail, 3. Buffalo wings, 4. Potato skins, 5. Salad Garden, 6. Caesar Entree T-bone steak, 7. Pot roast, 8. Lamb Side dish Corn, 9. Rice, 10. French fries, 11. Baked potato, 12. Pinto beans, 13. Dessert Chocolate cake, 14. Brownies, 15. Ice cream, 16. Apple pie

This is a combination problem requiring a combination solution with the following formula and steps:

C (n, r) =? C (n, r) = ?

n choose r

n (objects) = 16

r (sample) = 5

C (n, r) =? C (n, r) = ?

C (n, r) =C (14,5) C (n, r) =C (16,5)

=16! (5! (16−5)!) =16! (5! (16−5)!)

= 4368

3 0

3 years ago

How many integers in the set {n ∈ Z | 1 ≤ n ≤ 700} are divisible by 2 or 7?

sukhopar [10]

$\large\begin{array}{l}\\\\ \textsf{This question gives us a set}\\\\ \mathsf{S=\{n \in\mathbb{Z}:~1\le n\le 700\}}\\\\ \mathsf{S=\{1,\,2,\,3,\,\ldots,\,699,\,700\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 2 (even integers):}\\\\ \mathsf{A=\{n\in \mathbb{Z}:~n=2k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-4,\,-2,\,0,\,2,\,4,\,\ldots\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 7:}\\\\ \mathsf{B=\{n\in \mathbb{Z}:~n=7k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-14,\,-7,\,0,\,7,\,14,\,\ldots\}} \end{array}$

___________

$\large\begin{array}{l}\\\\ \textsf{We want to know how many elements there are in the}\\\textsf{following set:}\\\\ \mathsf{S\cap (A\cup B)=(S\cap A)\cup(S\cap B)\qquad(i)} \end{array}$

____________

$\large\begin{array}{l}\\\\ \bullet~~\mathsf{S\cap A=\{n\in\mathbb{N}:~n=2k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap A=\{2,\,4,\,6,\,\ldots,\,698,\,700\}}\\\\ \mathsf{S\cap A=\{1\cdot 2,\,2\cdot 2,\,3\cdot 2,\,\ldots,\,349\cdot 2,\,350\cdot 2\}}\\\\\\ \textsf{So, there are 350 elements in }\mathsf{S\cap A:}\\\\ \mathsf{\#(S\cap A)=350.} \\\\\\ \bullet~~\mathsf{S\cap B=\{n\in\mathbb{N}:~n=7k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap B=\{7,\,14,\,21,\,\ldots,\,693,\,700\}}\\\\ \mathsf{S\cap B=\{1\cdot 7,\,2\cdot 7,\,3\cdot 7,\,\ldots,\,99\cdot 7,\,100\cdot 7\}} \\\\\\ \textsf{So, there are 100 elements in }\mathsf{S\cap B:}\\\\ \mathsf{\#(S\cap B)=100.} \end{array}$

____________

$\large\begin{array}{l}\\\\ \textsf{Therefore,}\\\\ \mathsf{\#\big[S\cap (A\cup B)\big]}\\\\ =\mathsf{\#\big[(S\cap A)\cup(S\cap B)\big]}\\\\ =\mathsf{\#(S\cap A)+\#(S\cap B)-\#\big[(S\cap A)\cap(S\cap B)\big]}\\\\ =\mathsf{350+100-50}\\\\ =\mathsf{450-50}\\\\ =\mathsf{400~elements.}\\\\\\ \textsf{There are 400 integers in S that are divisible by 2 or 7.} \end{array}$

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$\large\begin{array}{l}\\\\ \textsf{Any doubts? Please, comment below.}\\\\\\ \textsf{Best wishes! :-)} \end{array}$

Tags: <em>set theory divibilility divisible integers union intersection</em>

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3 years ago

Find 6 tenths of 80cm

Rzqust [24]

Answer:

6/10 of 80 is 48

7 0

3 years ago

Read 2 more answers