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3 years ago

In the figure, BCND is a rectangle and CGNR is a rhombus. The area of BCND is 90 and BC = 10. What is 3GR?

Mathematics

1 answer:

PIT_PIT [208]3 years ago

6 0

Answer:

$3GR=27$

Step-by-step explanation:

Since area of rectangle BCND is given as 90 and one of its side is 10, the other side MUST be 9.

$CN*BC=90\\CN*10=90\\CN=9$

In Rhombus CGNR, CN and GR are congruent (property of Rhombus). Hence GR = 9 as well.

Thus 3GR = 3(9) = 27

First answer choice is right.

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Pls answer this simple question for brainly

eimsori [14]

Answer

The equation is already in slope intercept form so just graph it as you normally would.

Step-by-step explanation:

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2 years ago

108 centimeters equal how many meters?

Sveta_85 [38]

Answer:

1.08 meters

Step-by-step explanation:

Divide by 100 to find this out. 108/100 = 1.08

You can remember this by knowing that the "centi-" prefix means 100 (technically, 100ths). Just like you probably already know 100 cents in a dollar (USD) or 100 years in a century. Even the "cent" in percent means per hundred. There are 100 centimeters in a meter. A centimeter is about as wide as your little finger. A meter is close to a yard.

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2 years ago

Read 2 more answers

Don't have to do all of them just tell me the ones you do.

Alik [6]

See explanations below.

Step-by-step explanation:

12. If H(x) represent the percent of U.S households with internet use in x years after 1980 then;

a) H(23)=55 means the number of U.S households with internet use in 23 years after 1980 is 55

b)H(4)=k

so if in 23 years H, is 55, find in 1 year

In 1 year H= 55/23=k

c)H(27) ≥ 61 means in 27 years the number of U.S households with Internet use will be greater or equal to 61 households. If you check the results, in 27 years, H is 55/23 * 27 =64.5 ≅65 households which is at most 61 households.

d) H(17) + H(21)=H(29) means the sum of households with internet use in 17 years and 21 years after 1980 equal the number of households with internet use in 29 years.Checking the results;

H(17) = 55/23 *17 =40.65

H(21)=55/23 *21=50.22

H(17)+H(21)=40.65+50.22=90.87≅91 households

H(29)=55/23 * 29 = 69.34≅69 which is False

13.

h(x)=-7x ; h(x)=63 ⇒replacing x in the second function with -7x

-7x=63

x=63/-7

x=-9

14.

t(x)=3x ; t(x)=23

3x=23

x=23/3 = 7.67

14.

m(x) =4x +15 ; m(x)=7

4x+15=7

4x=7-15 -----------collecting like terms

4x=-7

x=-7/4

15.

k(x)=6x-12 ; k(x) =18

6x-12=18

6x=18+12-------collecting like terms

6x=30

x=30/6

x=5

16. q(x) =1/2x -3 , q (x) =-4

1/2 x-3 =-4------------multiply each term by 2

x-6= -8 ----------------collect like terms

x= -8+6

x= -2

17.

j(x)= -4/5 x + 7 ; j(x)= -5

-4/5 x +7 = -5 ---------multiply each term by 5

-4x+35= -25

-4x=-25-35

-4x=-60

4x=60

x=60/4

x= 15

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Functions ; brainly.com/question/2316114

Keywords : Functions

#Learnwithbrainly

3 0

3 years ago

How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used

MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the n-th term of the sequence, a (n), is given recursively by

• a (1) = 1

• a (n) = a (n - 1) + 21 … … … for n > 1

We can find the explicit rule for the sequence by iterative substitution:

a (2) = a (1) + 21

a (3) = a (2) + 21 = (a (1) + 21) + 21 = a (1) + 2×21

a (4) = a (3) + 21 = (a (1) + 2×21) + 21 = a (1) + 3×21

and so on, with the general pattern

a (n) = a (1) + 21 (n - 1) = 21n - 20

Now, we're told that the sum of some number N of terms in this sequence is 2332. In other words, the N-th partial sum of the sequence is

a (1) + a (2) + a (3) + … + a (N - 1) + a (N) = 2332

or more compactly,

$\displaystyle\sum_{n=1}^N a(n) = 2332$

It's important to note that N must be some positive integer.

Replace a (n) by the explicit rule:

$\displaystyle\sum_{n=1}^N (21n-20) = 2332$

Expand the sum on the left as

$\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332$

and recall the formulas,

$\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n$

$\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2$

So the sum of the first N terms of a (n) is such that

21 × N (N + 1)/2 - 20N = 2332

Solve for N :

21 (N ² + N) - 40N = 4664

21 N ² - 19 N - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

N = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer N for which the first N terms of the sum add up to 2332.

4 0

3 years ago

What is the axis of symmetry of a parabola if its x-intercepts are -3 and 5?

ollegr [7]

Answer:

The axis of symmetry will be at 1

Step-by-step explanation:

The middle of -3 and 5 will be the axis :)

-3, -2, -1, 0, 1, 2, 3, 4, 5

-2, -1, 0, 1, 2, 3, 4

-1, 0, 1, 2, 3

0, 1, 2

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4 years ago