Jonathan had to rent a car for one day while his car was getting fixed , the car rental costs $23 per day plus $2 for every mile
that has been driven. If jonathan spent not than $100 on a one-day car rental, which inequality can be solved to determine how many miles the car was driven?
The answer would be B because you're paying the $23 once while $2 for every mile which would be X and those two added together would be greater than the $100.
Let be Z the money ; We have ( 40 / 100 ) x Z = $85 ; ( 4 / 10 ) x Z = $85 ; ( 2 / 5 ) x Z = $85 ; Z = $( 85 x 5 ) ÷ 3 ; Z = $425 ÷ 3 ; Z = $141,66 ≈ $142 ;