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vodka [1.7K]
3 years ago
11

HELP PLEASE!?!

Mathematics
2 answers:
Law Incorporation [45]3 years ago
8 0
Multiply to negative 60 add to negative 11
Vladimir [108]3 years ago
3 0
The attached pic shows each step.

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Apply the product rules to determine the sign of each expression
sammy [17]

Answer:

Step-by-step explanation:

1). (\frac{-4}{9})\times (\frac{7}{4})=(-1)(\frac{4}{9})(\frac{7}{4} )

                =-\frac{7}{9} [Negative]

2). (-2\frac{3}{4})(-1\frac{1}{5})=(-1)(2\frac{3}{4})(-1)(1\frac{1}{5})

                        =(-1)^2(2\frac{3}{4})(1\frac{1}{5})

                        =(2\frac{3}{4})(1\frac{1}{5}) [Positive]

3). (3)(-3)(-3)(-3)(-3) = 3.(-1).3.(-1).3.(-1).3(-1).(3)

                              = (-1)⁴(3)⁵

                              = (3)⁵ [Positive]

4). (-\frac{1}{6})(-2)(-\frac{3}{5})(-9) = (-1)(\frac{1}{6})(-1)(2)(-1)(\frac{3}{5})(-1)(9)

                                   = (-1)^4(\frac{1}{6})(2)(\frac{3}{5})(9)

                                   = (\frac{1}{6})(2)(\frac{3}{5})(9) [Positive]

5). (-\frac{4}{7})(-\frac{3}{5})(-9)=(-1)(\frac{4}{7})(-1)(\frac{3}{5})(-1)(9)

                            =(-1)^3(\frac{4}{7})(\frac{3}{5})(9)

                            =-(\frac{4}{7})(\frac{3}{5})(9) [Negative]

6). (-\frac{10}{7})(\frac{8}{3})=(-1)(\frac{10}{7})(\frac{8}{3})

                    =-(\frac{10}{7})(\frac{8}{3}) [Negative]

3 0
3 years ago
Read 2 more answers
________________________________
KIM [24]

Answer:

The Red block is the answer

Step-by-step explanation:

6 0
3 years ago
The law of cosines reduces to the Pythagorean theorem whenever the triangle is acute. true or false
inysia [295]
False- the included angle must be a right angle for cos C to be 0 & two other points are normally used
6 0
3 years ago
Read 2 more answers
Help with question 2a and b?
Aleonysh [2.5K]
If it is a single transformation, it will need to be a homothetic transformation.
None of the points remain at the old place, so it cannot be a scaling problem with respect to one of the existing points.

A homothetic transformation is bacically a scaling problem, with respect to an arbitrary point called the homothetic centre.
The centre, O,  if it exists, is along the point joining any original point and the transformed point.

Here, take a pencil (imaginary one if you wish) and join points AA', BB', CC', DD', EE' and you will find that they are concurrent at point O (3,-6).
So O(3,-6) is the centre of homothety.

The scale factor, as usual, is AO/A'O, or BO/B'O... for transformation from X to Y  (X is ABCDE), or the reciprocal if it is from Y to X.


7 0
3 years ago
8y3 + 8y3 <br><br> It’s combining like terms
Sauron [17]

Answer:

16y³

Step-by-step explanation:

8y³ + 8y³ = 16y³

It's like 8 + 8, but you also have the y³

6 0
3 years ago
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