The sample proportion has an approximately normal distribution, with the mean being the population mean and the standard deviation (i.e. the standard error of the sampling proportion) equal to
SE = sqrt(p*q/n) where p is the population proportion q is 1-p, and n is the sample size.
<span>(Typically, for a confkdence interval, the sample proportion and its complement are substituted for p and q.) </span>
The margin of error will be Zc*SE, where Zc is the critical value of Z for the level of confidence required. The confidence interval, then, will be the sample proportion, plus or minus the margin of error.
For a 90% confidence interval, Zc is 1.645.
<span>So the margin of error is 1.645 * sqrt(.9*.1/400), roughly .025. So your confidence interval would be around [.875, .925]
The best and most correct answer among the choices provided by your question is the second choice or letter C which is 3%.
I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span>
B 6hrs 40 minutes
30000 / 75 = 400
400 minutes put into hours is 6 hours 40 minutes
D=20/3 or in decimal form d=6.666, it keeps going
-vp+40<95
subtract 40 from each side
-vp < 55
divide by -p (which flips the inequality) assuming p>0
v > -55/p
Answer:
As you included no picture, I do not know the time on the clock. We can however, work with assumed figures which you can then relate to your question.
Assuming the time on the clock was 10:45 am, if the family took 2 hours and 15 minutes to get to the camp ground, simply subtract this from 10:45 to find out what time they arrived.
Subtract the 2 hours from 10am:
= 10 - 2
= 8am
Subtract the 15 minutes from 45:
= 45 - 15
= 30
Put that together:
= 8:30 am
<em>They left their house at 8:30 am using this scenario. </em>
