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3 years ago

I need help, please I have until 9 p.m. to finish it number 3 homework

Mathematics

1 answer:

sergeinik [125]3 years ago

6 0

Answer: 1/3

<u>Step-by-step explanation:</u>

When adding or subtracting fractions, they must have the same denominator.

$\dfrac{5}{9}-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{5}{9}\bigg(\dfrac{6}{6}\bigg)-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{30}{54}-\boxed{\dfrac{?}{?}}=\dfrac{12}{54}\\\\\\\dfrac{30}{54}-\boxed{\dfrac{18}{54}}=\dfrac{12}{54}\\\\\\\text{Simplify}\quad \dfrac{18}{54}\div \dfrac{18}{18}\quad =\large\boxed{\dfrac{1}{3}}$

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given the function f(x) = 2^x, find the value of f−1(32). (1 point) f−1(32) = 0 f−1(32) = 1 f−1(32) = 5 f−1(32) = 16

EastWind [94]

Answer:

Step-by-step explanation:

The inverse of $f(x)=2^x$ is $g(x)=\log_2(x)$ .

$g(32)=\log_2(32)$

$\log_2(32)=5$ since $2^5=32$ .

$g(32)=\log_2(32)=5$

Note: In general, the inverse of $f(x)=a^x$ is $g(x)=\log_a(x)$ .

7 0

3 years ago

Estimate the sum or difference.

dangina [55]

1) $\frac{4}{6}+\frac{1}{8}=\frac{19}{24}$

2) $\frac{2}{6}+\frac{7}{8}=\frac{29}{24}$

3) $\frac{5}{6}-\frac{3}{8}=\frac{11}{24}$

4) $\frac{4}{6}+\frac{3}{8}=\frac{25}{24}$

5) $\frac{7}{8}-\frac{5}{6}=\frac{1}{24}$

6) $\frac{1}{6}+\frac{7}{8}=\frac{25}{24}$

Step-by-step explanation:

In order to calculate the sum of two fractions, we first have to find the lowest common denominator of the two fractions, then multiply the numerator of each fraction by the ratio between the lowest common denominator and the original denominator, and then add/subtract the two new numerators.

$\frac{4}{6}+\frac{1}{8}=$

Here the lowest common denominator between 6 and 8 is 24,

So we have to rewrite each fraction as having denominator 24: this means that we have to multiply both numerator and denominator of the 1st fraction by 4 (because 24/6=4), and both numerator and denominator of the 2nd fraction by 3 (because 24/8=3).

So the new numerators of the two fractions are:

$4\cdot 4 = 16\\1\cdot 3 = 3$

The expression then becomes:

$\frac{4}{6}+\frac{1}{8}=\frac{16}{24}+\frac{3}{24}=\frac{16+3}{24}=\frac{19}{24}$

$\frac{2}{6}+\frac{7}{8}=$

Here the lowest common denominator between 6 and 8 is again 24,

so we have again to multiply both numerator and denominator of the 1st fraction by 4, and both numerator and denominator of the 2nd fraction by 3.

So the new numerators of the two fractions are:

$2\cdot 4 = 8\\7\cdot 3 = 21$

And we get:

$\frac{2}{6}+\frac{7}{8}=\frac{8}{24}+\frac{21}{24}=\frac{8+21}{24}=\frac{29}{24}$

$\frac{5}{6}-\frac{3}{8}$

The denominators are the same, so the lowest common denominator is always 24. So we can adopt the same procedure, and new numerators are:

$5\cdot 4 = 20\\3\cdot 3 = 9$

And so:

$\frac{5}{6}-\frac{3}{8}=\frac{20}{24}-\frac{9}{24}=\frac{20-9}{24}=\frac{11}{24}$

$\frac{4}{6}+\frac{3}{8}=$

Using the same lowest common denominator, 24, the new numerators are:

$4\cdot 4 = 16\\3\cdot 3 = 9$

And so we can rewrite the expression as

$\frac{4}{6}+\frac{3}{8}=\frac{16}{24}+\frac{9}{24}=\frac{16+9}{24}=\frac{25}{24}$

$\frac{7}{8}-\frac{5}{6}=$

Again, the lowest common denominator is 24. This time the denominator of the 1st fraction is 8 while the denominator of the 2nd fraction is 6, so we have to multiply the numerator of the 1st fraction by 3 and the numerator of the 2nd fraction by 4.

We get:

$7\cdot 3 = 21\\5\cdot 4 = 20$

So the expression will be rewritten as:

$\frac{7}{8}-\frac{5}{6}=\frac{21}{24}-\frac{20}{24}=\frac{21-20}{24}=\frac{1}{24}$

$\frac{1}{6}+\frac{7}{8}=$

Here the situation is similar to the first 4 exercises: using 24 as lowest common denominator, the numerators become

$1\cdot 4 = 4\\7\cdot 3 = 21$

So the expression becomes

$\frac{1}{6}+\frac{7}{8}=\frac{4}{24}+\frac{21}{24}=\frac{4+21}{24}=\frac{25}{24}$

Learn more about fractions:

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3 years ago

What is algebraic expression/equation

adell [148]

An algebraic expression is an expression built up from integer constants, variables, and the algebraic operations.

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2 years ago

A two-factor between-subjects design is evaluated. The F-value for Factor A has df = 1, 40 and the F-value for Factor B has df =

finlep [7]

Answer:

The df values for the A x B interaction are also 3,40

Step-by-step explanation:

The F-value for Factor A has df = 1, 40

The F-value for Factor B has df = 3, 40.

The df values for the A x B interaction are also 3,40

This is because the source of variation between columns has ( c- 1); rc(n-1) degrees of freedom and the source of variation between rows has (r-1); rc(n-1) degrees of freedom and the source of variation of interaction

(between rows and columns) has ( c-1) ( r-1); rc(n-1) degrees of freedom.

Therefore

Factor A: ( c- 1); rc(n-1) = 1,40

<u>Factor B: (r-1); rc(n-1) = 3,40</u>

Interaction : ( c-1) ( r-1); rc(n-1) = 3*1,(40)= 3,40

where c refers to columns , r refers to rows and n refers to the total sample size.

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2 years ago

He needs the height of the coop to be 2 feet shorter than the width and needs the length of the coop to be 10 feet longer than t

meriva

2feeet don’t understand what your asking

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3 years ago