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barxatty [35]
3 years ago
14

Agan Interior Design provides home and office decorating assistance to its customers. In normal operation, an average of 2.5 cus

tomers arrive each hour. One design consultant is available to answer questions and make product recommendations. The consultant averages 10 minutres with each customer.
A. Compute the operating characteristics of the customers wiating line, assuming posson arrivals and exponential service times.

B. Service goals dictate that an arriving customer should not wait for service more than an average of 5 minutes. Is this gaol being met?

C. If the consultant can reduce the average time spent per customer to 8 minutes, what is the mean service rate? Will the service goal be met?
Business
1 answer:
Phantasy [73]3 years ago
6 0

Answer:

A) Single-server single-phase model (M/M/1).

\lambda=2.5 \,customers/hour\\\\\mu=6\,customers/hour

B) The goal is not met, as the average time waiting for service is 5.56 minutes.

C) The new mean service rate is 7.5 customers/hour.

In this case, the average time waiting for service is 4 minutes, so the goal is met.

Explanation:

A) This situation can be modeled as a single-server single-phase model (M/M/1).

The mean arrival rate is 2.5 customers per hour.

\lambda=2.5 \,customer/h

The mean service rate is 6 customers per hour, calculated as:

\mu=\frac{60\, min/h}{10 \,min/customer}=6\, customer/h

B) The average waiting time for a customer can be expressed as:

W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda}  =\frac{2.5}{6}\frac{1}{6-2.5} =0.417*0.222=0.093\,hours\\\\W_q=0.093\,hours*(60min/h)=5.56 \,min

The average waiting time is 5.56 minutes, so it is more than the goal of 5 minutes.

C) If the average time spent per customer to 8 minutes, the mean service rate becomes

\mu=\frac{60\, min/h}{8 \,min/customer}=7.5\, customer/h

An the average waiting time for the service now becomes:

W_q=\frac{\lambda}{\mu}\frac{1}{\mu-\lambda}  =\frac{2.5}{7.5}\frac{1}{7.5-2.5} =0.333*0.2=0.067\,hours\\\\W_q=0.067\,hours*(60min/h)=4 \,min

The average time is now 4 minutes, so the goal is achieved.

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Answer:

No journal is needed

Par value  is now $1

Explanation:

There is journal entry for stock split no new funds were received from stockholders and the fact that the equity stockholders capital remain the same after the stock split.

It is a mere book redenomination where the number of outstanding shares in issue is increased while the par value is reduced  proportionally.

In essence a stock split of 2 for 1 means one share is added to existing one and the two shares are now priced at the value of one previously

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International Imports (I2) pays an annual dividend rate of 10.20% on its preferred stock that currently returns 13.67% and has a
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Answer:

The market price/value of the share of preferred stock is $74.62

Explanation:

The preferred stock pay 10.2% return on $100 per share which comes out to be 100 * 10.2% = $10.2. This dividend will remain constant no matter what the price in the market is. The price in the market is calculated by dividing the ineterest payment by the current price of the share. The formula for the current return of the preferred stock is:

0.1367 = 10.2 / P

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3 years ago
Wizard Co. purchased two machines for $250,000 each on January 2, 2005.
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Answer:

B. $275,000

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The second machine will be depreciate over time as it can later be used for operational purposes or another research projects. The first, as can only be used for a  research project It should be considered expenses for the entire amount regardless of the useful life.

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The adjustment to record supplies used during the period would​ be:
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4 years ago
What will be the depreciation, via the straight line method, if the cost of a plant is $43,250, estimated disposal value is $3,2
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Answer:

depreciation expense per year 8,000

Explanation:

<u>The first step,</u> is to calculate the depreciable amount for the asset:

cost - salvage value = amount subject to depreciation

43,250 - 3,250 = 40,000 = depreciable amount

<u>Then,</u> we calculate the depreciation per year:

depreciable amount/ useful life = depreciation per year

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In some particular cases, the first year the asset enter the accounting it could be for a period of half the accounting period, so only half-year depreciation is appliedon the first year.

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