Question

Number 6 please and thank you

Answer 1

length of the cylinder = 8 x 20 mm

= 160 mm

radius of the cylinder = 20 mm

so,

volume of the container = πr^2h

$= \frac{22}{7} \times {20}^{2} \times 160$

= 201142.8571 mm^3

volume of four ornaments ,

$= 4 \times \frac{4}{3} \times \frac{22}{7} \times {20}^{3}$

=134095.2381 mm^3