Answer:
Solution given:
f(x)=x²
g(x)=x+5
h(x)=4x-6
now
23:
(fog)(x)=f(g(x))=f(x+5)=(x+5)²=x²+10x+25
24:
(gof)(x)=g(f(x))=g(x²)=x²+5
25:
(foh)(x)=f(h(x))=f(4x-6)=(4x-6)²=16x²-48x+36
26:
(hof)(x)=h(f(x))=h(x²)=4x²-6
27;
(goh)(x)=g(h(x))=g(4x-6)=4x-6+5=4x-1
28:
(hog)(x)=h(g(x))=h(x+5)=4(x+5)-6=4x+20-6=4x-14
Answer:
The area of the figure is 1,000 square feet
Step-by-step explanation:
we know that
The area of the kite ABCD
is equal to
![A=\frac{1}{2}[AC*BD]](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5BAC%2ABD%5D)
where
AC and BD are the diagonals of the kite
we have

substitute
![A=\frac{1}{2}[40*50]=1,000\ ft^2](https://tex.z-dn.net/?f=A%3D%5Cfrac%7B1%7D%7B2%7D%5B40%2A50%5D%3D1%2C000%5C%20ft%5E2)
What is the problem?? I would love to help
0 Pretend that is theta XD
cot 0 =
Find tan 0.
tan 0 = 
tan 0 = 
tan 0 = 
cot 0 =
cot 0 =
Multiply 2/√5 to the numerator and the denominator (or multiply the reciprocal of the denominator to the top and bottom of the fraction)
cot 0 = 
cot 0 =
Multiply √5 to the numerator and the denominator
cot 0 = 
cot 0 = 
Answer:
The solution is X<18
Step-by-step explanation:
When Mason was solving the inequality he subtracted two from the equation instead of adding two to solve for x.
X-2<16
X<18