You need use your strategies multiplie it than simplify to k and than move it to E tens
Answer:
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Step-by-step explanation:
The equation for the volume of a pyramid of base area B and height h is
V = (1/3)·B·h. Here, V = 432 ft³, B = (12 ft)² and h (height of the pyramid) is unknown. First we find the height of this pyramid, and then the slant height.
V = 432 ft³ = (144 ft²)·h, so h = (432 ft³) / (144 ft²) = 3 ft.
Now to find the slant height of this pyramid: That height is the length of the hypotenuse of a right triangle whose base length is half of 12 ft, that is, the base length is 6 ft, and the height is 3 ft (as found above).
Then hyp² = (3 ft)(6 ft) = 18 ft², and the hyp (which is also the desired slant height) is hyp = √18, or √9√2, or 3√2 ft.
The slant height of the pyramid is 3√2 ft, or to the nearest tenth ft,
4.2 ft
Probability = no of outcomes / total outcomes
First draw = no of blue mables / total mables = 3 / (4 + 3 + 3) = 3/10
For the second draw, since there was no replacement of the first draw, the blue mables has reduced by one, and the total mables has reduced by one.
Second draw = no of remaining blue mables / total remaining mables = 2/9
Probability for both draws = 3/10 x 2/9 = 1/15
For the first one use the slope formula:

So for you that would look like this:

For number 2, in order for a slope to be 0, it has to be a completely horizontal line with no steepness whatsoever. That can ONLY happen with lines that are "y=some constant with no x". So that answer has to be y = -5. For that last one, we have to use the slope-intercept form of a line and use the point they give us along with the slope to find the y-intercept, or the "b". That looks like this for us:

so b= 5/6. So our equation, fitting the slope and y intercept back in, gives us