Answer:
The answer is ""
Step-by-step explanation:
Distance
midpoint height
let
Gradient
Perpendicular Gradient
midpoints
Similar to perpendicular
Now I'll obtain the perpendicular bisector solution
An equation of the center circle radius will be
.
Answer:
115.48
Step-by-step explanation:
This shape can be split into two distinct shapes
Two halves of a semi circle, and a rectangle in between
Circle:
Putting both halves of the semi circle together will give you a full circle. The diameter of the circle is given (7m).
The area of a circle is A = π
The radius, r, is half of the diameter, so 7 / 2 = 3.5m
A = π
A = π *
A = 38.38
Rectangle:
The area of a rectangle is A = h b
The height, h, is known at 7m
The base, b, can be found by removing the length from the dot to the end of the semi circles. This length is the radius of the semi circles, 3.5m
Removing the radius from the total length given
18 - 3.5 - 3.5 = 11m
The base is 11m
A = h b
A = 7 * 11 = 77
Total Area = Circle area + Rectangle area
Total Area = 38.38 + 77 = 115.48
Answer:
(a) The velocity after 2 second is 5.9 m/s
The velocity after 4 second is -13.7 m/s.
(b) The projectile reaches its maximum height after 2.60 s of projection.
(c)The maximum height that is attained by the projectile is 37.18 m.
(d)Therefore the projectile hits the ground after 5.36 seconds of projection.
(e)The velocity of the projectile when it hits the ground is 27.03 m/s
Step-by-step explanation:
Given that, a projectile shot vertically upward from a point 4 m above the ground with a initial velocity of 25.5 m/s.
The height of the projectile after t seconds is
where h is in meter.
(a)
We use the formula
v=u+at
V= final velocity
u = initial velocity = 25.5 m/s
a = acceleration= acceleration due to gravity= 9.8 m/s²
Since the object moves upward direction and acceleration due to gravity is downward direction. So here a= -9.8 m/s.
v(2)= 25.5+(-9.8)×2
=25.5-19.6
=5.9 m/s
And when t= 4
v(4)= 25.5+(-9.8)×4
=25.5-39.2
= -13.7 m/s
The velocity after 2 second is 5.9 m/s
The velocity after 4 second is -13.7 m/s.
(b)
At its maximum height,the velocity of the projectile is zero. i.e v=0
∴0=25.5+(-9.8)t
⇒9.8t=25.5
⇒t = 2.60 s
The projectile reaches its maximum height 2.60 s after projection.
(c)
To find the maximum height, we are putting t= 2.60 in this equation .
=37.18 m
The maximum height that is attained by the projectile is 37.18 m.
(d)
When the projectile hits the ground the height will be zero i.e h=0
From the equation of height we get
⇒t= -0.15 ,5.36
Therefore it hits the ground after 5.36 seconds of projection.
(e)
To find the velocity we use the formula v=u+at
Here v = final velocity=?
u=25.5 m/s,
t = 5.36 s
a= -9.8m/s²
v=25.5+(-9.8)5.36
= -27.03 m/s
Negative sign denoted that the motion of the projectile is downward direction.
The velocity of the projectile when it hits the ground is 27.03 m/s.