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Zigmanuir [339]
2 years ago
13

A 12​-sided die is rolled. The set of equally likely outcomes is ​{1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 com

ma 9 comma 10 comma 11 comma 12​}. Find the probability of rolling a number less than 14.
Mathematics
2 answers:
LenKa [72]2 years ago
7 0

Answer:

  1

Step-by-step explanation:

It is certain that the number rolled will be less than 14, so the probability is 1.

ohaa [14]2 years ago
5 0

Answer:

1

Step-by-step explanation:

Probability is the chance or likelihood that an event will occur.

Probability = Expected number of outcomes/Total outcomes

If a 12sides die is rolled, the sample space is (1,2,3,4,5,6,7,8,9,10,11,12)

The total number of sample space is the total outcome = 12

To find the probability of rolling a number less than 14 means, probability of getting values less than 14. As we can see, the values less than 14 that are in the sample space is also 12(i e all the numbers)

Expected outcome = 12

Probability = 12/12 = 1

This probability is known as a sure event because it is 1

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Given sin θ = 7/25, find the value of a and b in the following statements.
Sergeu [11.5K]

Answer:

a = 7, b = 24 if quadrant 1

a = -7, b = -24 if quadrant 2

Step-by-step explanation:

Tan theta = sin(theta) × sec(theta)

a/24 = (7/25) × (25/b)

ab = 168

a = 168/b

1 + tan²(theta) = sec²(theta)

1 + a²/576 = 625/b²

1 + 168²/576b² = 625/b²

1 = 576/b²

b = 24 (+ or -)

a = 168/24 = 7 (+ or -)

3 0
2 years ago
Read 2 more answers
I need to show my work for this answer. Solve for x
ale4655 [162]

Answer:

natoooooooy natoooooy natooooy

Step-by-step explanation:

natoooooooy

3 0
2 years ago
A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar
zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a Pr = \frac{2}{110}

b Pr = \frac{72}{110}

Step-by-step explanation:

Given

n = 11 --- hammers

r = 2 --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

Pr = P(D) * P(D)

Pr = \frac{2}{11} * \frac{2-1}{11-1}

Pr = \frac{2}{11} * \frac{1}{10}

Pr = \frac{2}{110}

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

P(D') = \frac{9}{11}

For two selections, the probability that all are not defective is:

Pr = P(D') * P(D')

Pr = \frac{9}{11} * \frac{9-1}{11-1}

Pr = \frac{9}{11} * \frac{8}{10}

Pr = \frac{72}{110}

8 0
2 years ago
2) Does each table below show equivalent ratios? Explain your reasoning.
pogonyaev

Answer:

Refractive index of a medium depends upon the refractive index of the surroundings

7 0
2 years ago
Read 2 more answers
On a rectangular hyperbola, if one point is (2, 3) and y varies inversely to x, find y when x is 6.
pickupchik [31]

Answer:

y = 1

Step-by-step explanation:

y is inversely proportion to x means that ,

y ∝ 1/x or ,

y\  \alpha\  \frac{1}{x}

When we remove the proportionality sign we get,

y=k(\frac{1}{x})\\y=\frac{k}{x} \\

now we know the point is (2 , 3) which means it corresponds to (x , y) which furthermore means y=3 when x=2,

so we insert these values and get the value of k.

y=\frac{k}{x} \\\\3=\frac{k}{2}\\\\6=k\\

now the equation becomes,

y=\frac{6}{x}

now we need to find y when x is 6 so just replace x with 6

y=\frac{6}{x}\\\\y=\frac{6}{6} \\\\y=1

so we get the value of y is 1

6 0
2 years ago
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