Answer:
Plug in a Y value into Y and a X value into X and if both sides aren't equal the statement isnt true .....
Given: In ΔDEF and ΔDGF, Side DF is common.
To prove congruent of the triangle, we must require the minimum three conditions; like two sides and one angle of one triangle should be equal to the other triangle. OR Three sides of one triangle should be equal to the other triangle. OR Two angles and one side of one triangle should be equal to the other triangle. etc.
As per given question, to prove congruent of given triangles by SAS property then we should have given two sides and one angle of one triangle should be equal to the other triangle as additional information.
Since, In ΔDEF and ΔDGF, Side DF is common. So, we should require only one side and one angle that should be equal to another triangle.
Answer:
Step-by-step explanation:
For this question they are asking you to find y when x is {2, 4, and 6}
That means you need to plug 2,4, and 6 into the equation and solve.
For example:
f(x) = 5x - 4
f(2) = 5(2) - 4
f(2) = 10 - 4
f(2) = 6
f(x) = 5x - 4
f(4) = 5(4) -4
f(4) = 20 - 4
f(4) = 16
f(x) = 5x - 4
f(6) = 5(6) - 4
f(6) = 30 - 4
f(6) = 26
So in my opinion I think u have to do 20-4=16 so 16 students like the museum! Sorry if I’m wrong
Parent function: f(x)=sqrt(x)
Transformations:
1) Reflect the graph across the x-axis: f(x) changes sign:
h(x)=-f(x)→h(x)=-sqrt(x)
2) and shift it upward 3 units: We must add 3 units to the function:
g(x)=h(x)+3→g(x)=-sqrt(x)+3
Answer: Option C. g(x)=-sqrt(x)+3
