I'm not 100% sure but this is how I would try.
If you don't get a better answer, check this w/your teacher.
x/100 *90,000 = 1200
90,000x = 120,000
x = 1.3% tax percentage
1.3/100x = 2200
1.3x = 220,000
x = $169,230.77 assessed value
Answer:
Step-by-step explanation:
inland city has the coldest winter and warmest summer.
inland city, since it has a higher median of around 14.5 Celsius while coastal city has around 14 degrees Celsius
I would prefer to live in coastal city, since it has a smaller range of temperatures. Also, it has nice and mild weather: it has warmer winters than inland city, and cooler summers than inland city.
Using proportions, it is found that there is a 0.54 = 54% probability that a randomly selected household owns a cat.
<h3>What is a proportion?</h3>
A proportion is a fraction of total amount.
In this problem, the proportions associated with owning a cat are given by:
- 70% of 60%(also have a dog).
- 30% of 40%(do not have a dog).
Hence:
p = 0.7(0.6) + 0.3(0.4) = 0.42 + 0.12 = 0.54.
0.54 = 54% probability that a randomly selected household owns a cat.
More can be learned about proportions at brainly.com/question/24372153
Answer:
750 people will come in at 15 hours.
Step-by-step explanation:
350 divided by 7=50 50 times 15=750
sorry i don't know the rest
Simplify each term<span>.</span>
Simplify <span>3log(x)</span><span> by moving </span>3<span> inside the </span>logarithm<span>.
</span><span>log(<span>x^3</span>)+2log(y−1)−5log(x)</span><span>
</span>
Simplify <span>2log(y−1)</span><span> by moving </span>2<span> inside the </span>logarithm<span>.
</span><span>log(<span>x^3</span>)+log((y−1<span>)^2</span>)−5log(x)</span><span>
</span>
Rewrite <span>(y−1<span>)^2</span></span><span> as </span><span><span>(y−1)(y−1)</span>.</span><span>
</span><span>log(<span>x^3</span>)+log((y−1)(y−1))−5log(x)</span><span>
</span>
Expand <span>(y−1)(y−1)</span><span> using the </span>FOIL<span> Method.
</span><span>log(<span>x^3</span>)+log(y(y)+y(−1)−1(y)−1(−1))−5log(x)</span><span>
</span>
Simplify each term<span>.
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>x^<span>−5</span></span>)</span><span>
</span>Remove the negative exponent<span> by rewriting </span><span>x^<span>−5</span></span><span> as </span><span><span>1/<span>x^5</span></span>.</span><span>
</span><span>log(<span>x^3</span>)+log(<span>y^2</span>−2y+1)+log(<span>1/<span>x^5</span></span>)</span><span>
</span>
Combine<span> logs to get </span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))
</span><span>log(<span>x^3</span>(<span>y^2</span>−2y+1))+log(<span>1/<span>x^5</span></span>)
</span>Combine<span> logs to get </span><span>log(<span><span><span>x^3</span>(<span>y^2</span>−2y+1)/</span><span>x^5</span></span>)</span><span>
</span>log(x^3(y^2−2y+1)/x^5)
Cancel <span>x^3</span><span> in the </span>numerator<span> and </span>denominator<span>.
</span><span>log(<span><span><span>y^2</span>−2y+1/</span><span>x^2</span></span>)</span><span>
</span>Rewrite 1<span> as </span><span><span>1^2</span>.</span>
<span><span>y^2</span>−2y+<span>1^2/</span></span><span>x^2</span>
Factor<span> by </span>perfect square<span> rule.
</span><span>(y−1<span>)^2/</span></span><span>x^2</span>
Replace into larger expression<span>.
</span>
<span>log(<span><span>(y−1<span>)^2/</span></span><span>x^2</span></span>)</span>