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Marina CMI [18]
3 years ago
13

The moon is 384,403 km from earth. Estimate how many quarters laid end to end it would take to reach the moon if a quarter has a

diameter of .9055
Mathematics
1 answer:
aniked [119]3 years ago
8 0

Answer:

The number of quarters is about 16,713\ quarters

Step-by-step explanation:

we know that

The diameter of a quarter is 0.9055 in

The moon is 384,403 km from earth

To find out the number of quarters, divide the distance of the Moon from the Earth by the diameter of one quarter

step 1

Convert inches to  kilometers

1\ in=2.54*10^{-5}\ km

0.9055\ in=0.9055*2.54*10^{-5}=2.3*10^{-5}\ km

step 2

Find the number of quarters

384,403/2.3*10^{-5}=16,713\ quarters

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2x

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How to solve |y|&gt;4.5
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Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers
OleMash [197]

Answer:

∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9

Step-by-step explanation:

From Sine rule

\frac{a}{sinA}=\frac{b}{sinB} = \frac{c}{sinC}

∴ b / sinB = c / sinC

From the question,

b = 129, c = 168 and ∠B = 48°

∴ 129 / sin48° = 168 / sinC

Then, sinC = (168×sin48)/129

sinC = 0.9678

C = sin⁻¹(0.9678)

C = 75.42

∠C2=75.4°

and

∴∠C1 = 180° - 75.4°

∠C1 =104.6°

For ∠A

∠A1 = 180° - (104.6°+48°) [sum of angles in a triangle]

∠A1 = 27.4°

and

∠A2 = 180° - (75.4° + 48°)

∠A2 = 180° - (123.4°)

∠A2 = 56.6°

For side a

a1/sinA1 = b/sinB

a1/ sin27.4° = 129/sin48

a1 = (129×sin27.4°)/sin48

a1 = 79.8845

a1 = 79.9

and

a2/sinA2 = b / sinB

a2/ sin56.6° = 129/sin48

a2 = (129×sin56.6°)/sin48

a2 = 144.9184

a2 = 144.9

Hence,

∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9

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3 years ago
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