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olya-2409 [2.1K]
2 years ago
5

PLEASE HELP!! I’ll give brainliest pleas

Mathematics
1 answer:
777dan777 [17]2 years ago
8 0

Answer:

it's A

Step-by-step explanation:

I took teg quiz and got a 100

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Serjik [45]

Answer:

685.75

Step-by-step explanation:

650*0.055+650

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Oblicz ułamki 2/8=.../4
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3 years ago
Anton unpacks 4 dozen glasses from a box. he finds 5/12 of the glasses are broken. how many glasses are broken?
Nesterboy [21]
20 out of the 48 glasses are broken.
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3 years ago
Which of the following equations describes the line shown below? Check all<br> that apply.
scoundrel [369]

Answer:

B. y = 2x - 2

E. y + 4 = 2(x + 1)

F. y - 6 = 2(x - 4)

Step-by-step explanation:

The equation of the line can be found using either the point-slope equation or the slope-intercept equation.

✔️Equation of the line in point-slope using the slope and the coordinates of the point (4, 6):

Slope = m = change in y/change in x

Using (4, 6) and (-1, -4),

m = (-4 - 6)/(-1 - 4)

m = -10/-5

m = 2

Substitute m = 2, and (a, b) = (4, 6) into the point-slope equation form y - b = m(x - a)

Thus:

y - 6 = 2(x - 4)

✔️Equation of the line in point-slope using the slope and the coordinates of the point (-1, -4):

Slope = m = 2

Substitute m = 2, and (a, b) = (-1, -4) into the point-slope equation form y - b = m(x - a)

Thus:

y - (-4) = 2(x - (-1))

y + 4 = 2(x + 1)

✔️Equation of the line in slope-intercept form, y = mx + b

Where,

m = slope = 2

b = y-intercept = -2 (the point where the line intercepts the y-axis)

Thus, substitute m = 2 and b = -2 into y = mx + b

y = 2x + (-2)

y = 2x - 2

6 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
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