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3 years ago

Landon borrowed a book from the library

Mathematics

1 answer:

Anastaziya [24]3 years ago

6 0

Tell Landon to bring back the book and he won't owe any moneyyyyy ;DDd
Because
the library charges late fees as well.

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Shari purchased 87 erasers at the rate of $3 per eraser. She sold 63 of them at the rate of $3.50 per eraser and the remaining a

Bad White [126]

Answer:

<h2>12.1% profit</h2>

Step-by-step explanation:

Given data

total eraser= 87

cost =$3 each

Total cost of eraser= 87*3= $261

she sold 63 at $3.5

1. sales made for the 63= $220.5

2 sale made for the remaining= 87-63=24

24*3=$72

Total sales made = 220.5+72=$292.5

her profit= sales-cost

profit= 292.5-261=$31.5

therefore the percent profit is

=31.5/261*100

=0.12*100

=12.1%

8 0

2 years ago

How much does a glass cube with a side of 5-cm weigh if 1cm3 of glass weighs 2 2/5 grams?

PtichkaEL [24]

The weight of galss cube with side 5 cm is 300 grams

<em><u>Solution:</u></em>

A glass cube is of side length 5 cm

Let us first find the volume of glass cube

<em><u>The volume of cube is given as:</u></em>

$volume = (side)^3\\\\volume =5^3 = 125$

Thus volume of cube is 125 $cm^3$

Given that,

$1 cm^3 = 2\frac{2}{5} \text{ grams }\\\\1 cm^3 =\frac{12}{5} \text{ grams}$

So, weight of 125 cubic centimeter of glass cube is found by multiplying weight of 1 cubic centimeter of glass cube by 125

$\text{ Weight of 125 } cm^3 \text{ cube } = \text{ Weight of 1 } cm^3 \text{ cube } \times 125$

$\text{ Weight of 125 } cm^3 \text{ cube } = \frac{12}{5} \times 125 = 25 \times 12 = 300$

Thus weight of galss cube with side 5 cm is 300 grams

3 0

3 years ago

Read 2 more answers

How many flowers spaced every 4 inches are needed to surround a circular garden with a 15-foot radius? Round all circumference a

charle [14.2K]

Answer:

283 flowers

Step-by-step explanation:

c=2pi*r

c = 1130.973 =1131

1131/4

282.75 = 283

4 0

2 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .

6 0

3 years ago

Can someone help me please?! I'll give brainlest for correct answer

mojhsa [17]

1.) The answers:

A) BME

B) MER

C) Mm

D) xBy

E) Straight

F) REB

G) MEB and BER

H) xBy

3 0

2 years ago