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attashe74 [19]
3 years ago
12

The symbol 3! means 3x2x1 which equals 6. Similarly, 5! means 5x4x3x2x1, which equals 120, and so on. Suppose that N! ends in ex

actly 3 zeros after fully multiplying out. What is the smallest value that N can have?
PLS EXLPLAIN AND HELP
Mathematics
2 answers:
tangare [24]3 years ago
4 0

Answer:

15 should be your answer

GOOD LUCK

Step-by-step explanation:

Vladimir79 [104]3 years ago
3 0

Answer:

15

Step-by-step explanation:

1! = 1, which contains no zeroes at the end

5! = 120, which contains 1 zero at the end

10! = 3628800, which contains 2 zeroes at the end

15! = 1307674368000, which contains 3 zeroes at the end

Therefore, the smallest value that N can have is 15

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A factory produce bicycles at a rate of 110+0.5t^2-0.9t bicycles per week (t in weeks)
klasskru [66]

Answer:

221

Step-by-step explanation:

Day 8 is the first day of the second week.

Day 21 is the last day of week 3.

We need to know the n umber of bicycles made from t = 1 to t = 3

The function is b(t) = 110 + 0.5t^2 - 0.9t, where t is in weeks.

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\int_{1}^{3} (110 + 0.5t^2 - 0.9t) dt

\int_{1}^{3} (110 + \dfrac{t^2}{2} - \dfrac{9t}{10}) dt

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Answer: 221

3 0
3 years ago
Urgent, please i will give brainliest
Ne4ueva [31]

Answer:

1. \frac{\sqrt{13} }{3}

2. 3.2362

3. \frac{60}{11}

Step-by-step explanation:

1.

Cot is the trigonometric ratio defined by "adjacent" over "opposite". <em>So, adjacent = 2 and opposite = 3.</em>

By pythagorean theorem, we have the "hypotenuse" as  \sqrt{2^2+3^2}=\sqrt{13}

Csc is defined as the trig ratio "hypotenuse" over "opposite". <em>We know the sides, so Csc \theta = \frac{\sqrt{13} }{3}</em>

<em />

<em>First answer choice is right.</em>

<em />

2.

By definition, Csc \theta is the inverse of Sine \theta. <em>If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:</em>

Csc\theta=\frac{1}{0.3090}\\=3.2362

Third answer choice is right.

3.

By definition tan and cot are inverse of each other. <em>So the value of tan is the reciprocal of the value of cot.</em> We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

Cot\theta=\frac{60}{11}

Third answer is right.

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