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attashe74 [19]
2 years ago
12

The symbol 3! means 3x2x1 which equals 6. Similarly, 5! means 5x4x3x2x1, which equals 120, and so on. Suppose that N! ends in ex

actly 3 zeros after fully multiplying out. What is the smallest value that N can have?
PLS EXLPLAIN AND HELP
Mathematics
2 answers:
tangare [24]2 years ago
4 0

Answer:

15 should be your answer

GOOD LUCK

Step-by-step explanation:

Vladimir79 [104]2 years ago
3 0

Answer:

15

Step-by-step explanation:

1! = 1, which contains no zeroes at the end

5! = 120, which contains 1 zero at the end

10! = 3628800, which contains 2 zeroes at the end

15! = 1307674368000, which contains 3 zeroes at the end

Therefore, the smallest value that N can have is 15

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Dafna1 [17]

\frac{x}{y}Answer:

Six would be your answer

Step-by-step explanation:

2y-9= y-2

-y        -Y

y-9=-2

y=-2+9

y=6

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3 years ago
Please help as soon as possible
Inessa [10]

Answer:

tan=Opposite/Adjacent so 3/4 is the answer

Step-by-step explanation:

3 is opposite of A and 4 is Adjacent  of A

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6 0
3 years ago
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Kona wants to bake at most 30 loaves of banana bread and nut bread for a bake sale. Each loaf of banana bread sells for $2.50, a
frutty [35]

x+y≤30 and 2.50x+2.75y≥44 are the inequalities that model given situation.

Step-by-step explanation:

Given,

Number of banana breads and nut breads to bake = at most 30

At most 30 means the amount cannot exceed 30.

Selling price of each banana bread = $2.50

Selling price of each nut bread = $2.75

Amount to make = $44 at least

At least 44 means that the amount cannot be less than 44.

Let,

x represent the number of loaves of banana bread to be sold

y represent the number of loaves of nut bread to be sold

x+y≤30

2.50x+2.75y≥44

x+y≤30 and 2.50x+2.75y≥44 are the inequalities that model given situation.

Keywords: linear inequalities, addition

Learn more about linear inequalities at:

  • brainly.com/question/4793866
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3 years ago
What is the formula to calculate the area of a square/rectangle
emmasim [6.3K]
Area of square/rectangle = length times width
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3 years ago
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slavikrds [6]

Answer:

a) \frac{dm}{dt} = -k\cdot m, b) m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }, c) m(t) = 10\cdot e^{-\frac{t}{2438.155} }, d) m(300) \approx 8.842\,g

Step-by-step explanation:

a) Let assume an initial mass m decaying at a constant rate k throughout time, the differential equation is:

\frac{dm}{dt} = -k\cdot m

b) The general solution is found after separating variables and integrating each sides:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where \tau is the time constant and k = \frac{1}{\tau}

c) The time constant is:

\tau = \frac{1690\,yr}{\ln 2}

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m(t) = 10\cdot e^{-\frac{t}{2438.155} }

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4 0
3 years ago
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