Question

The symbol 3! means 3x2x1 which equals 6. Similarly, 5! means 5x4x3x2x1, which equals 120, and so on. Suppose that N! ends in exactly 3 zeros after fully multiplying out. What is the smallest value that N can have?
PLS EXLPLAIN AND HELP

Answer 1

Answer:

15 should be your answer

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Step-by-step explanation:

Answer 2

Answer:

15

Step-by-step explanation:

1! = 1, which contains no zeroes at the end

5! = 120, which contains 1 zero at the end

10! = 3628800, which contains 2 zeroes at the end

15! = 1307674368000, which contains 3 zeroes at the end

Therefore, the smallest value that N can have is 15