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NikAS [45]
3 years ago
14

2. which of the following correctly identifies active transport?

Biology
2 answers:
kotykmax [81]3 years ago
8 0
Active transport is a phenomena of the movement of molecules move from a region of lower concentration to a region of higher concentration across a cell membrane. <span>Osmosis follows the same scheme of movement of the molecules through the membrane. The difference is that diffusion does not need a membrane to transfer the molecules across.</span>
Serhud [2]3 years ago
3 0

Answer: 2) Active transport can be defined as the movement of molecules across a membrane from a lower concentration region to higher concentration region in the direction against a concentration gradient. Active transport spend cellular energy to achieve this movement.

The active transport is of two types namely primary active transport and secondary active transport. Primary active transport use ATP as a energy for the movement while secondary active transport uses electrochemical energy for their transport.

Answer: 3) Osmosis is the movement of solvent particles across a semi-permeable membrane from dilute solution in to a concentrated solution.

Diffusion is the movement of particle from area of higher concentration to lower concentration without any semi-permeable membrane. The overall effect is to equalize the concentration throughout the medium.

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A dump truck can hold 2 tons of gravel. The pay loader loading the truck puts 750 pounds of gravel in the truck at one time. How
Georgia [21]
So 4000/750=5.3repeating so 6 because he has to move allll the gravel
4 0
3 years ago
What method(s) do plants use to obtain nitrogen? Select all that apply.
elena-14-01-66 [18.8K]

Answer:

Plants can't use N2 as is so the first option is wrong. They do have relationships with bacteria that live in nodules of the root and convert the nitrogen into ammonia, a usable form for the plants. So the second option is correct. There are bacteria living in the soil as well that convert nitrogen to ammonia so technically option 3 is also correct. Again, nitrogen if present in water would be in the form N2 which is not usable by plants so 4 is wrong.

These are correct:

use bacteria to convert nitrogen to usable form

In obtain usable nitrogen compounds from the soil

4 0
3 years ago
Identify the process that is necessary for sexual reproduction. Also, explain why it is necessary and identify how this process
Olenka [21]

Answer:

The correct answer would be meiosis.

In diploid organisms, meiosis is the process that results in the formation of four haploid daughter cells from single diploid parent cell. Each of the daughter cell contains half the number of chromosomes present in parent cell.

It results in the formation of haploid gametes (sperm in males and eggs in females) which is essential in the process of sexual reproduction.

The fusion of gametes results in the formation of diploid zygote that is, maintains the diploid nature of the organism.

Hence, in absence of meiotic division the chromosomal number would keep on doubling after each generation.

In addition, crossing over (exchange of genetic material between non-sister chromatids) also takes in the prophase-I of meiosis I. It increases the genetic variation within organisms of the species. It may add survival adaptations to the population.

5 0
3 years ago
Read 2 more answers
Imagine a very large population of moths that is isolated from gene that you are studying flow. A single gene controls wing colo
svlad2 [7]

Answer:

B. p will neither increase nor decrease; it will remain more or less constant under the conditions described

Explanation:

When a population is in Hardy-Weinberg equilibrium, it is not evolving and allele frequencies are not going to change across generations. Conditions for a population to be in Hardy-Weinberg equilibrium are :

  • Infinite population size
  • Random mating
  • No selection
  • No mutation
  • No gene flow

Since the moth population in question shows above mentioned characteristics, it is in Hardy-Weinberg equilibrium. Frequency of none of the alleles are going to change.

Hence, p will neither increase nor decrease; it will remain more or less constant under the conditions described.

5 0
3 years ago
2. If you were to design a predator-prey relationship using a planktonic rotifer as the predator and a single celled green
Bond [772]

Answer:

I WOULD IN HANCE THE OPRATINS TO A BIG NUMBER

Explanation:

3 0
3 years ago
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