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Inga [223]
3 years ago
9

-4y+8-3x+4y+9+5x= Need help

Mathematics
2 answers:
lord [1]3 years ago
7 0

Answer:

2x+17

Step-by-step explanation:

-4y+8-3x+4y+9+5x

Combine like terms

-3x +5x    -4y +4y    +8+9

2x             +0             +17

bezimeni [28]3 years ago
6 0

Answer:

2x+17

Step-by-step explanation:

-4y+8-3x+4y+9+5x=

-4y+4y-3x+5x+8+9

2x+17

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I need help ASAP. Thank you :)
kvasek [131]

m∠FDE = 52°

Solution:

Given data:

DE ≅ DF, CD || BE, BC || FD and m∠ABF = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠ABF + m∠CBF = 180°

116° + m∠CBF = 180°

m∠CBF = 64°

If CD || BE, then CD || BF.

Hence CD || BE and BE || FD.

Therefore BFCD is a parallelogam.

<em>In parallelogram, Adjacent angles form a linear pair.</em>

m∠CBF + m∠BFD = 180°

64° + m∠BFD = 180°

m∠BFD = 116°

<em>Sum of the adjacent angles in a straight line = 180°</em>

m∠BFD + m∠DFE = 180°

116° + m∠DFE = 180°

m∠DFE = 64°

we know that DE ≅ DF.

<em>In triangle, angles opposite to equal sides are equal.</em>

m∠DFE = m∠DEF

m∠DEF = 64°

<em>sum of all the angles of a triangle = 180°</em>

m∠DFE + m∠DEF + m∠FDE = 180°

64° + 64° + m∠FDE = 180°

m∠FDE = 52°

8 0
3 years ago
Write as a decimal number.<br> 9-10
Ad libitum [116K]

Answer:

.9

Step-by-step explanation:

9 divided by 10

8 0
2 years ago
Find the inverse function for
kifflom [539]
\bf \stackrel{f(x)}{y}=\sqrt{2x-6}\qquad \qquad \stackrel{f^{-1}(x)}{y}=\cfrac{x^2+6}{2}

that is correct hmmmm, yes, I think the restriction is also correct, it has to be x > 0, because, the domain on the original, has a restriction of x⩾3, otherwise the radicand turns negative.

now, the graph of that original function is a parabola sideways opening to the right, if you include both sides of the vertex of the parabola, it will not pass the vertical-line-test and not be a function, but if you restrict it to only positive roots, so it'll only be on the 1st quadrant, then it functions ok.

that means, the range of the original function, has to stick to only 0 or positive root values, now, recall that the range of the original is the domain of the inverse.  Therefore, the domain of the inverse, will have to stick to only 0 or positive values, since it's bound to the same restriction as the original's range.

notice the picture below of both, the dashed section is the positive range for each, if you include it, the original will fail the vertical-line-test, and the inverse will fail the horizontal-line-test.

recall that for a function to have an inverse, they both must pass the vertical and horizontal line test, or be a one-to-one functions.

6 0
3 years ago
WILL GIVE BRAINLIEST WILL GIVE BRAINLIEST
Alex73 [517]

Answer:

9

Step-by-step explanation:

7 0
2 years ago
Answer all of these and I will give you 35 points!!!!!!!!!!!!!!!!!!!!!
aev [14]

9.   LCM of    <u><em>9, 12, and 15</em></u>        is   <u><em>180</em></u>

12.  LCM of  <em><u>15, 18, and 30</u></em>      is   <u><em>90</em></u>

15.  LCM of   <u><em>40 and 1</em></u>      is   <u><em>40</em></u>

16:  factors of <u><em>24</em></u> :    <em>1,2,3,4,6,8,12,  and 24</em>

17:  factors of <u><em>63</em></u> :     <em><u>1, 2, 4, 8, 16, 32 and 64.</u></em>

18:  factors of <u><em>50</em></u> :    <em><u>1, 2, 5, 10, 25, and 50</u></em>

19:   LCM of : <u><em>3 , 2 , 7</em></u><em>  </em>  is  <u><em>42</em></u>

20:  LCM of : <u><em>15 , 2</em></u>        is  <u><em>30</em></u>

21:   LCM of : <u><em>45,  30 </em></u><em>    </em>is <u><em>90</em></u>

<h2 />

7 0
2 years ago
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