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2 years ago

Translate and solve using proportions: What number is 30% of 60

Mathematics

2 answers:

balandron [24]2 years ago

3 0

Answer: 18

Step-by-step explanation:

The question is asked to know 30% of 60, we get

60 x 30% = 60 x 0.3 = 18

Pepsi [2]2 years ago

3 0

Answer:

Step-by-step explanation:

We know that 30% means 30/100

30/100 multiplied by 60

hence, the answer is 18

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What is the answer to this problem

Georgia [21]

The formula for volume of a cone = PI x r^2 x h/3

PI = 3.14

r = 8.5/2 = 4.25

h = 4.5

Volume = 3.14 x 4.25^2 x 4.5/3

Volume = 3.14 x 18.0625 x 1.5

Volume = 85.074375

Rounded to the nearest hundredth = 85.07 cubic cm.

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2 years ago

Find the perimeter of the one following shape, rounded to the nearest tenth:

aalyn [17]

The perimeter would be 65.6

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3 years ago

(1 point) A rectangular storage container with an open top is to have a volume of 12 cubic meters. The length of its base is twi

Vlada [557]

Answer:

The cost of the materials for the cheapest such container is approximately $249.8

Step-by-step explanation:

The volume the rectangular container is to have = 12 m³

The base length = 2 × The width of the base

The cost of the material for the base = 11 dollars/m²

The cost of the other sides = 9 dollars/m²

Let 'l', 'w', and 'h' represent the length and width of the base and the height of the rectangular storage container respectively, we have;

l = 2·w

l × w × h = 12 m³

∴ h = 12/(l × w) = 12/(2·w × w) = 6/w²

The cost of the open top rectangular container = The cost of the base + The cost of the 4 sides

The cost of the base = The area of the base × $11/m²

∴ The cost of the base = l × w × 11 =2·w × w × 11 = 22·w²

The cost of the 4 sides = The area of the four sides × $9/m²

∴ The cost of the 4 sides = 2 × (l × h + w × h) × 9

The cost of the 4 sides = 2 × (2·w × 6/w² + w × 6/w²) × 9 = 18 × (12/w + 6/w) = 324/w

∴ The cost of the open top rectangular container = 22·w² + 324/w

The coefficient of w² in the equation of the cost is positive, therefore, the cost of the materials for the cheapest such container, 'C', is given by value of 'w' at the minimum point of the equation, 22·w² + 324/w, which is given by the equating the derivative of the equation to zero as follows;

d(22·w² + 324/w)/dw = 0

∴ 44·w - 324/w² = 0

∴ 44·w = 324/w²

w³ = 324/44 = 81/11

w = ∛(81/11)

∴ C = 22·w² + 324/w = 22 × (∛(81/11))² + 324/(∛(81/11)) = 486/(∛(81/11)) ≈ 249.8

The cost of the materials for the cheapest such container, C ≈ $249.8

3 0

2 years ago

A rectangular poster is 3 times as long as it is wide. A rectangular banner is 5 times as long as it is wide. Both the banner an

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