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2 years ago

11

a ball rebounds one-half the distance that it falls. If the ball is dropped from a height of 512 feet how high does it go on its

8th rebound?

2 answers:

Kay [80]2 years ago

7 0

The ball wil bounce 2 feet on the eighth bounce

Serjik [45]2 years ago

6 0

You can easily put this into a calculator by taking the number 512 and multiply by .5^x where x is the number of bounces the ball does.

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What is the value of x?<br><br> Enter your answer, as a decimal, in the box.

iragen [17]

Answer:

x = 67.50 ft

Step-by-step explanation:

Consider, ΔMAB and ΔMNP,

∠M = ∠M (Common)

Given AB║NP and let MN as transversal,

∠MAB = ∠MNP (alternate angle)

Also, Given AB║NP and let MP as transversal,

∠MBA = ∠MPN (alternate angle)

Therefore, ΔMAB ≅ ΔMNP (By AAA similarity )

Thus, by CPCT,

$\frac{MA}{MN}=\frac{MB}{MP}=\frac{AB}{NP}$

consider first two ratios,

$\frac{MA}{MN}=\frac{MB}{MP}$

Substitute the values, MA = MN - AN = 49.5 ft

$\frac{49.5}{71.5}=\frac{x}{97.5}$

On solving for x , we get, x = 67.50 ft

Thus, value of x is 67.50 ft

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sergiy2304 [10]

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