Using pseudocode:
printArray(arr[], integers)
DECLARE integers
integers = SizeOf(arr)
FOR i = 1 to integers // loop from 1 to the number of elements in arr[]
print(i)
print('')
i = i + 1
ENDFOR
END
With
and
, we have



Then
has critical points where


where
is any integer.
is increasing wherever
, which happens for


Answer:
12 girls.
Step-by-step explanation:
24 ÷ 2 = 12
(This is divided to find out 1 part of the whole class as ⅓)
⅓ = 12
1 (whole) take away ⅔ = ⅓
Since ⅔ + ⅓ = 1
⅓ = fraction of girls in class
1 part = 12
So ⅓ = 12 girls out of 36 total students
Hope this helps. :)
Hello:
3x²+5x+2=0
delta = (5)²-4(3)(2)=1
x =( -5 <span>±1)/6
x= -2/3 or x=-1
t4-81=(t²)² -9² = (t²-9)(t²+9) =(t-3)(t+3)(t²+9)....(answer B)</span>