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KIM [24]
4 years ago
14

Identify the graph described by the function p(x)=x/10 for x=1,2,3,4

Mathematics
1 answer:
san4es73 [151]4 years ago
7 0

Answer:

Graph A is correct

Step-by-step explanation:

p(x)= x/10

x= 1, 2, 3, 4

Plug in x  values in p(x)

when x=1 , then P(1) = 1/10

When x=2 , then P(2) = 2/10

When x=3 , then P(3) = 3/10

When x=4 , then P(4) = 4/10

In the graph y axis has 2/10 , 4/10 , 6/10...

1/10 lies between 0  and 2/10

3/10 lies between 2/10 and 4/10

Graph A is correct

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Given: AB = 12
Alexxx [7]

In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

<h3>What is the proof about?</h3>

Note that:

AB = 12

AC = 6.

BC = AB - AC

= 12 - 6

=6

So, AC, BC= 6

Since C is in the middle, one can say that C is the midpoint of AB.

Note that the use of segment addition property shows: AC + CB = AB = 12

Since it has Symmetric property, AC = 6 and Subtraction property shows that CB = 6

Therefore,  AC = CB and thus In proving  that C is the midpoint of AB, we see truly that C has Symmetric  property.

See full question below

Given: AB = 12 AC = 6 Prove: C is the midpoint of AB. A line has points A, C, B. Proof: We are given that AB = 12 and AC = 6. Applying the segment addition property, we get AC + CB = AB. Applying the substitution property, we get 6 + CB = 12. The subtraction property can be used to find CB = 6. The symmetric property shows that 6 = AC. Since CB = 6 and 6 = AC, AC = CB by the property. So, AC ≅ CB by the definition of congruent segments. Finally, C is the midpoint of AB because it divides AB into two congruent segments. Answer choices: Congruence Symmetric Reflexive Transitive

Learn more about midpoint from

brainly.com/question/6364992

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2 years ago
What are you post to do when you have a decimal that is 0.09
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9/100=0.09 also

i hoped i help :)
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4 years ago
Which point lies on the graph of Y= 4x-4<br> 1.(0,4)<br> 2.(0,-4)<br> 3.(-4,0)<br> 4.(4,0)
statuscvo [17]

Answer:

<h2>2. (0, -4)</h2>

Step-by-step explanation:

y=4x-4\\\\\text{Substitute the coordinates of each points to the equation}\\\text{and check the equality.}\\\\1.\ (0,\ 4)\to x=0,\ y=4\\\\4=4(0)-4\\4=0-4\\4=-4\qquad\bold{FALSE}\\\\2.\ (0,\ -4)\to x=0,\ y=-4\\\\-4=4(0)-4\\-4=0-4\\-4=-4\qquad\bold{TRUE}\\\\3.\ (-4,\ 0)\to x=-4,\ y=0\\\\0=4(-4)-4\\0=-16-4\\0=-20\qquad\bold{FALSE}\\\\4.\ (4,\ 0)\to x=4,\ y=0\\\\0=4(4)-4\\0=16-4\\0=12\qquad\bold{FALSE}

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3 years ago
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