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3 years ago

Answer as quickly as possible

Mathematics

2 answers:

Anestetic [448]3 years ago

7 0

Answer:

Midpoint of AB found by averaging the coordinates, so (3, -4.5)

Equation of line connecting that to origin (0,0) given by y - 0 = ((-4.5-0)/(3-0)) * (x-0)

y = -(3/2)x

Step-by-step explanation:

serious [3.7K]3 years ago

5 0

Answer

3x-2y=12 is a required equation of a line

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The events committee buys 80 flowers for a school dance. The flowers are a combination of carnations and roses. Each carnation c

Slav-nsk [51]

Answer:

64 carnations and 16 roses.

Step-by-step explanation:

The events committee buys 80 flowers

The flowers are a combination of carnations and roses.

Each carnation costs $0.50 and each rose costs $2.50

The committee spends a total of $72

<u>Solution:</u>

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Let there be (c) carnations and (r) roses.

So,

c + r = 80 flowers

and $0.50c + $2.50 = $72

This forms a simultaneous equation:

c + r = 80 ... (i)

0.5c + 2.5r = 72 ... (ii)

Multiplying equation (i) by 0.5 and equation (ii) by 1 gives;

0.5c + 0.5r = 40 ... (i)

0.5c + 2.5r = 72 ... (ii)

Subtracting (i) from (ii) gives;

0c + 2r = 32

2r = 32

r = 32 ÷ 2 = 16

Therefore, there are 16 roses

and 80 - 16 = 64 carnations

7 0

3 years ago

Please help!!!!! pls pls pls

Sidana [21]

Answer:

It’s b

Step-by-step explanation:

3 0

3 years ago

What is 3 and 4/9 - 2 and 5/6 PLEASE HELP DUE TOMORROW

Natasha_Volkova [10]

Answer:

3&4/9-2&5/6 = 11/18

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers

Find the volume of a pyramid with a square base where the side length of the base is 16.6 and the height of the pyramid is 9.1

photoshop1234 [79]

Answer:

835.865333

Step-by-step explanation:

16.6×16.6=275.56

275.56×9.1=2507.596

2507.596÷3=835.865333

8 0

2 years ago

(10x^3y^-2/5x^-3y^4)^-3, x≠0, y≠0

zhenek [66]

Answer:

$\dfrac{y^{18}}{8x^{18}}$

Step-by-step explanation:

The applicable rules of exponents are ...

(a^b)(a^c) = a^(b+c)

a^-b = 1/a^b

(a^b)^c = a^(bc)

Your expression simplifies as follows:

$\left(\dfrac{10x^3y^{-2}}{5x^{-3}y^4}\right)^{-3}=(2x^{3-(-3)}y^{-2-4})^{-3}=(2x^6y^{-6})^{-3}\\\\=(2^{-3})x^{6(-3)}y^{(-6)(-3)}=\dfrac{1}{8}x^{-18}y^{18}\\\\=\boxed{\dfrac{y^{18}}{8x^{18}}}$

6 0

4 years ago

Answer as quickly as possible​

Answer as quickly as possible