Using conditional probability, it is found that there is a 0.4235 = 42.35% probability that the patient really is HIV positive.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
- is the probability of both A and B happening.
- P(A) is the probability of A happening
In this problem:
- Event A: positive test.
- Event B: HIV positive.
The percentages involving a positive test are:
- 95% of 3%(positive)
- 4% of 100 - 3 = 97%(not positive).
Hence:
The probability of both having a positive test and being HIV positive is:
Then, the conditional probability is:
0.4235 = 42.35% probability that the patient really is HIV positive.
A similar problem is given at brainly.com/question/14398287
Answer:
Step-by-step explanation:
y = 4.8x + C
53.8 = 4.8(4) + C
53.8 = 19.2 + C
C = 34.6
Answer:
(-2,-2)
Step-by-step explanation:
The local minimum is a turning point of the graph.
From the graph, there is a turning point at (-2,-2).
This is the local minimum on the interval (-6,2).
This is the least point this interval.
That is why it is called local minimum.
Answer:
count up from negative 2. -1, 0, 1, 2, 3, 4, and 5. Now how many numbers did you count up? 7. The answer is 7.