Hello :
<span>the nth term in a geometric sequence where is ;
an = a1 ×qn .... q : common ratio a1 the first term
exempl :
C) an = 2×3^n-1
an =2×3^n ×3^-1
an =(2/3)×3^n
a1 = 2/3 and q= 3
same method for : D
</span>
Answer:
The maximum amount of sand in ounces that the company allows for each bottle is 25.5 ounces.
Step-by-step explanation:
The amount of sand that the company Sandy stores allows in each small bottle is determined by the amount of sand required for the bottle size plus the error in the amount of sand for the bottle size.
Now since each small bottle contains 25 ounces of sand and the error in the amount of sand contained in the bottle is 0.5 ounces, the amount of sand contained in the bottle = required amount ± error.
For the minimum amount, we subtract the error and for the maximum amount, we add the error.
Since the maximum amount is required, we have,
Maximum amount = required amount + error
required amount = 25 ounces and error = 0.5 ounces. So, Maximum amount = 25 ounces + 0.5 ounces = 25.5 ounces.
So, the maximum amount of sand in ounces that the company allows for each bottle is 25.5 ounces.
Answer:
(1) -5
Step-by-step explanation:
Put the value where the variable is, read the graph, and do the arithmetic.
g(2) = 3f(2) -2 = 3(-1) -2
<em> g(2) = -5</em>
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<em>Additional comment</em>
f(2) is the point on the graph where it is 2 units to the right of the y-axis. At that point, the graph is 1 unit below the x-axis, so f(2) = -1.
B. Rolling an even or not on the first says nothing about the second dice
