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SVEN [57.7K]
3 years ago
9

The quotient of two times a number and 5 is no more than 14.

Mathematics
1 answer:
OlgaM077 [116]3 years ago
7 0

Answer:

2x/5 <14

Step-by-step explanation:

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PLSS HELP ME WITH THIS
kolbaska11 [484]

Answer:

127

Step-by-step explanation:

400+1495=1895

1895/15=126.333333333

8 0
3 years ago
A slitter assembly contains 48 blades. Five blades are selected at random and evaluated each day of sharpness. If any dull blade
Alex73 [517]

Answer:

Part a

The probability that assembly is replaced the first day is 0.7069.

Part b

The probability that assembly is replaced no replaced until the third day of evaluation is 0.0607.

Part c

The probability that the assembly is not replaced until the third day of evaluation is 0.2811.

Step-by-step explanation:

Hypergeometric Distribution: A random variable x that represents number of success of the n trails without replacement and M represents number of success of the N trails without replacement is termed as the hypergeometric distribution. Moreover, it consists of fixed number of trails and also the two possible outcomes for each trail.

It occurs when there is finite population and samples are taken without replacement.

The probability distribution of the hyper geometric is,

P(x,N,n,M)=\frac{(\limits^M_x)(\imits^{N-M}_{n-x})}{(\limits^N_n)}

Here x is the success in the sample of n trails, N represents the total population, n represents the random sample from the total population and M represents the success in the population.

Probability that at least one of the trail is succeed is,

P(x\geq1)=1-P(x

(a)

Compute the probability that the assembly is replaced the first day.

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly N = 48.

Number of blades selected at random from the assembly  n= 5

Number of blades in an assembly dull is M  = 10.

The probability mass function is,

P(X=x)=\frac{[\limits^M_x][\limits^{N-M}_{n-x}]}{[\limits^N_n]};x=0,1,2,...,n\\\\=\frac{[\limits^{10}_x][\limits^{48-10}_{5-x}]}{[\limits^{48}_5]}

The probability that assembly is replaced the first day means the probability that at least one blade is dull is,

P(x\geq 1)=1- P(x

(b)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly  N = 48

Number of blades selected at random from the assembly  N = 5

Number of blades in an assembly dull is  M = 10

From the information,

The probability that assembly is replaced (P)  is 0.7069.

The probability that assembly is not replaced is (Q)  is,

q=1-p\\= 1-0.7069= 0.2931

The geometric probability mass function is,

P(X = x)= q^{x-1} p; x =1,2,....=(0.2931)^{x-1}(0.7069)

The probability that assembly is replaced no replaced until the third day of evaluation is,

P(X = 3)=(0.2931)^{3-1}(0.7069)\\=(0.2931)^2(0.7069)= 0.0607

(c)

From the given information,

Let x be number of blades dull in the assembly are replaced.

Total number of blades in the assembly   N = 48

Number of blades selected at random from the assembly  n = 5

Suppose that on the first day of the evaluation two of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M  = 2.

P(x=0)=\frac{(\limits^2_0)(\limits^{48-2}_{5-0})}{\limits^{48}_5}\\\\=\frac{(\limits^{46}_5)}{(\limits^{48}_5)}\\\\= 0.8005

Suppose that on the second day of the evaluation six of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M  = 6.

P(x=0)=\frac{(\limits^6_0)(\limits^{48-6}_{5-0})}{(\limits^{48}_5)}\\\\=\frac{(\limits^{42}_5}{(\limits^{48}_5)}\\\\= 0.4968

Suppose that on the third day of the evaluation ten of the blades are dull then the probability that the assembly is not replaced is,

Here, number of blades in an assembly dull is M

= 10.

P(x\geq 1)=1- P(x

 

The probability that the assembly is not replaced until the third day of evaluation is,

P(The assembly is not replaced until the third day)=P(The assembly is not replaced first day) x P(The assembly is not replaced second day) x P(The assembly is replaced third day)

=(0.8005)(0.4968)(0.7069)= 0.2811

5 0
3 years ago
What does P (A U B’) mean?
Savatey [412]

Answer:

It means or stands for the probably that either   A or B  occurs or both.

Step-by-step explanation:

It really isn't steps to it you just have to learn it.

8 0
3 years ago
What is the answer 4+3x = -2y
lilavasa [31]
First add 2y to both sides
so 4 + 3x + 2y = 0
then subtract 4 from both sides
so 3x + 2y = -4
that is standard form
now subtract 3x from both sides
2y = 3x - 4
now divide by 2 on both sides
y = 1.5x - 2
This is solved for y and is slope intercept form
starting from original subtract 4 from both sides
so 3x = -2x -4
now divide by 3 on both sides
so x = -2/3x -4/3
this is solved for x
hope any of that is what you needed.
6 0
3 years ago
13 FUNDRAISER The Cougar Pep Squad wants to sell T-shirts in the bookstore for
ANTONII [103]

Answer:

See attached worksheet.

Step-by-step explanation:

See attached worksheet for the table and graph.

I assume that "functation notation: simply means using x and y:  

  y = 2x + 3

The relationship between the number of T-shirts and cost is defined by y = 2t + 3, where:

y is the total cost,

x is the number of t-shirts,

the 2 is the cost for 1 t-shirt ($/t-shirt), and

3 is a one=time charge of $3 for each order.

The graph (attached) shows a straight line with a y-intercept of 3, the initial order fee.  It is linear since the cost of a t-shirt remains the same egardless of order size.

3 0
1 year ago
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