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Lerok [7]
4 years ago
14

Write a linear equation in slope intercept form to model the situation and internet company charges $4.95 per month plus $2.50 f

or each hour of use how much would it cost in a month when you use the internet for 14 hours
Mathematics
1 answer:
antoniya [11.8K]4 years ago
7 0

Answer:

it cost $39.95 in a month when you use the internet for 14 hours

Step-by-step explanation:

internet company charges $4.95 per month plus $2.50 for each hour

Let x be the amount of hours internet used

for 1 hour, charge is 2.50

for x hours , charge is 2.50x

To get linear equation we use y=mx+b

m is the slope and b is the fixed cost

fixed cost b= 4.95 and slope m = 2.50

So equation becomes y = 2.50x + 4.95

we need to find the cost y for 14 hours

So we plug in 14 for x  and find out y

y = 2.50(14) + 4.95= 39.95


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If 50 people go up the mountain and 40 people come down the mountain in a group then 7 people come down but then they go back up
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3 years ago
the jurassic zoo charged $11 for each adult admission and $8 for each child. the total bill for the 195 people from a school tri
Otrada [13]

Children : 144

Adults : 51

Explanation

Step 1

Set the equations

let

x represents the number of children

y represents the number of adults

charge per child:8

charge per adult:11

total people:195

then

a)the total people is 195, so

x+y=195\rightarrow equation(1)

b) the total bill was $1713,so

total childrend +total adults=173

but,

total adults cost= rate*number of adults

total children cost= rate*number of childe

replacing

8x+11y=1713\rightarrow equation(2)

Step 2

solve the equations,

\begin{gathered} x+y=195\rightarrow equation(1) \\ 8x+11y=1713\rightarrow equation(2) \end{gathered}

a) isolate the x value from equation 81) and replace in eqaution (2)

\begin{gathered} x+y=195\rightarrow equation(1) \\ \text{subtract y in both sides} \\ x+y-y=195-y \\ x=195-y \end{gathered}

replace in equation (2)

\begin{gathered} 8x+11y=1713\rightarrow equation(2) \\ 8(195-y)+11y=1713 \\ 1560-8y+11y=1713 \\ 3y+1560=1713 \\ \text{subtract 1560 in both sides} \\ 3y+1560-1560=1713-1560 \\ 3y=153 \\ \text{divide bothsides by 3} \\ \frac{3y}{3}=\frac{153}{3} \\ y=51 \end{gathered}

therefore, the number of adults is 51

b) now, replace the y value into equation (1) to find x

\begin{gathered} x+y=195\rightarrow equation(1) \\ x+51=195 \\ \text{subtract 51 in both sides} \\ x+51-51=195-51 \\ x=144 \end{gathered}

so, the number of children is 144

I hope this helps you

4 0
2 years ago
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