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TEA [102]
3 years ago
15

42) According to the 2000 Census the population of Canton was 7,720. Holly Spring's population was 3,200. Canton's population in

creases at a rate of 80 people a year and Holly Spring's population increases by 120 people a year. Which equation may be used to determine the number of years before the populations are equal?
Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0
Let's construct an equation for Canton's population increase as 7220+80n and Holly Spring's population increase with 3200+120n, where n is the number of years. We have to set these equations to each other in order to find when the population of these two places are equal. 3200+120n=7220+80n and n=100.5. After 100 and half years
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Answer:

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3 years ago
Brent purchased a used vehicle that depreciates under a straight-line method. The initial value of the car is $7500, and the sal
Ilia_Sergeevich [38]
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3 years ago
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Yuri [45]

Answer:

I think its right

Step-by-step explanation:

a) In the long run, we have, 5k=10 and k=2l Thus, C=2l+3l= 5l=0.5q Thus, AC=5l/10l =0.5 MC=0.5 b) In the short run, k=10 Q=min(50,10l) If l<5, q=10l. C=10+3l= 10+0.3q Thus, AC=10/q + 0.3 If l>5, q=50. C= 10+3l AC= (10+3l)/50 If q>50, then MC...

3 0
2 years ago
Can someone help me with number 4 and 12
Aliun [14]

Answer:

4 .c is the right answer

Step-by-step explanation:

16=100%

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7 0
3 years ago
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Use a Calculator!
Semenov [28]

The answer is 60 I think

7 0
2 years ago
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