Answer:
I got that AE^2 = 8EC^2
Step-by-step explanation:
Here's what I did. I probably did this wrong, but this might give you an idea on how to solve it.
First, create equations:
AB = BC = AC = DE = 2EC
BD= BC = EC
Then, I used pythagorean theorem (since AD is perpendicular to BC): AD^2 + DE^2 = AE^2
Substitute: (2EC)^2 + (2EC)^2 = AE^2
Simplify: 4EC^2 + 4EC^2 = AE^2
AE^2 = 8CE^2
Answer:
All 3 angles of any triangle have a sum = 180. Therefore, x + 2x + 3x = 180 6x = 180 x = 180/6 = 30. So It is a 30-60-90 special right triangle!!
Step-by-step explanation:
Answer:
B.
Step-by-step explanation:
(f-g)(x) = f(x) - g(x) =
= (3x³ + 8x² -7x - 4) - (2x - 6) = 3x³ + 8x² - 7x - 4 - 2x + 6 =
= 3x³ + 8x² - 9x + 2
<span>4 ft x 6 ft = 24 sq ft = 2160 sq in.
6 in. x 12 in. = 72 sq in.
(2160 sq in. / 72 sq in. = 30 large tiles.
30 large tiles to be used only.
The minimum cost is $</span>135.
im not nosy btw
Answer:
D(4) = -18
Step-by-step explanation:
D(n) = D(n – 1)(-6)
D(1) = 1/12
D(2) = D(2 – 1)(-6)
D(2) = D(1)(-6)
D(2) = 1/12 * (-6)
D(2) = -6/12
D(2) = -1/2
D(3) = D(3 – 1)(-6)
D(3) = D(2)(-6)
D(3) = -1/2 * (-6)
D(3) = 6/2
D(3) = 3
D(4) = D(4 – 1)(-6)
D(4) = D(3)(-6)
D(4) = 3 * (-6)
D(4) = -18