A food manufacturer makes 32-oz boxes of pasta. not every box weighs exactly 32 oz. The allowable difference from the ideal weig
ht is at most 0.05 oz. Write and solve an absolute value inequality to find the range of allowable weights.
I will give brainliest
2 answers:
Answer:
You are An army????
Step-by-step explanation:
Because I am an Army
Answer:
The range of allowable weights is between 31.95 oz and 32.05 oz both included
Step-by-step explanation:
w= allowable weights
I w-32 I ≤ 0.05
-0.05 ≤ w-32 ≤0.05
31.95 ≤ w ≤ 32.5
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I think the answer is B but i could be wrong
Answer:
Ray AC and Ray BC
Step-by-step explanation:
Taking commen 2 in RHS
p = 2 (L+W )
Divide by 2 on both sides.
p/2 = L+W
Subtract W on both sides.
p/2 - W = L
or L = p/2- W
HOPE IT HELPS YOU
Your answer is 160. Sorry about that answer above I laughed reading it hahaha.
Answer:
18+12.125π units²
Step-by-step explanation:
The diameter of the semicircle can be found by the use Pythagoras theorem.
Δx²+Δy²=d²
Δx=3--1=4
Δy=3--6=9
d²=4²+9²
d=√(16+81)
Area=πr²/2
=π×(√(16+81)/2)²÷2
=[π×(97)/4]/2
=97π/8
=18+12.125π units²
97π/8 is equivalent to 18+12.125π units²
