The equivalent expression of 25 - 64 are "a), b) and c)"
The given expression is:
25 - 64
To find, the equivalent expressions are:
a) 25 + 40x - 40x - 64
= 25 - 64, is the equivalent expression.
b) 25 + 13x - 13x - 64
= 25 - 64, is the equivalent expression.
c) (5 + 8)(5 - 8)
Using the algebraic identity,
(a + b)(a - b) =
=
= 25 - 64, is the equivalent expression.
d) ( + 13)( - 13)
Using the algebraic identity,
(a + b)(a - b) =
=
= - 169, is not a equivalent expression.
e)
Using the algebraic identity,
, is not a equivalent expression.
∴ The equivalent expression of 25 - 64 are "a), b) and c)".
Answer:
the right answer would be 13
Answer:
51/200
Step-by-step explanation:
To write a decimal as a fraction, you have to make the decimal the numerator, and put a multiple of ten with that number of zeroes in the denominator:
0.255 = 255/1000
Then we simplify
51/200
Answer:
2nd option
Step-by-step explanation:
You're goal is to isolate b by itself. The only part you need to worry about is the equation, the rest of the word problem is irrelevant.
The whole process of solving this is to do PEMDAS in reverse.
So first add/subtract all the values that does not have a <em>b</em> attach to it to the other side.
then multiply/divide all the values that is not a <em>b</em> to get the b-value by itself
Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2


Take the square of this result, to give k


Substitute 121 for k
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
The expression can be factorized as follows;




<em>Hence, the quadratic expression is </em>
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