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IRISSAK [1]
4 years ago
14

One alloy is 2 parts iron to 3 parts silver and another alloy is 7 parts iron to 3 parts silver. How much of each should be comb

ined to produce a 30 pound alloy that is 1 part iron to 1 part silver?
Mathematics
1 answer:
Shalnov [3]4 years ago
8 0
Let x be your first alloy
2/5x+7/10(30-x)=1/2(30)
4x+210-7x=150
3x=60
x=20
So, you need 20 lbs of the first alloy, and 10 parts of the second to make 30 lbs of half iron and half silver alloy!
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Step-by-step explanation:

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Multiply  11  by  4 .

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Multiply  3/ 1  by  11/ 11 .

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Multiply  3/ 1  and  11 /11 .

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Write  − 4  as a fraction with denominator  1 .

3 ⋅ 11 /11 + 44 ÷ 11 +  − 4 /1

Multiply  − 4 /1  by  11 /11 .

3 ⋅ 11 /11 + 44 ÷ 11 + − 4 /1  ⋅ 11 /11

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3 ⋅ 11 /11 + 44 ÷ 11 +   − 4 ⋅ 11 /11

Combine the numerators over the common denominator.

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33 + 44 − 44 /11

Simplify the expression.  

Add  33  and  44 .

77 − 44/ 11

Subtract  44  from  77 .

33 /11

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