Answer:
4
Step-by-step explanation:
Plug in 7 for d:
y= 1/2(7+1)
y=1/2(8) .... Adding what's in the parenthesis (PEMDAS)
y=4 ..... Multiply 1/2 by 8
Hope this helps:)
Answer:
25/324
Step-by-step explanation:
Make a table of possible products:
![\left[\begin{array}{ccccccc}&1&2&3&4&5&6\\1&1&2&3&4&5&6\\2&2&4&6&8&10&12\\3&3&6&9&12&15&18\\4&4&8&12&16&20&24\\5&5&10&15&20&25&30\\6&6&12&18&24&30&36\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccccccc%7D%261%262%263%264%265%266%5C%5C1%261%262%263%264%265%266%5C%5C2%262%264%266%268%2610%2612%5C%5C3%263%266%269%2612%2615%2618%5C%5C4%264%268%2612%2616%2620%2624%5C%5C5%265%2610%2615%2620%2625%2630%5C%5C6%266%2612%2618%2624%2630%2636%5Cend%7Barray%7D%5Cright%5D)
Of the 36 results, 10 are greater than 15.
The probability the product is greater than 15 on a single roll is 10/36 = 5/18.
The probability the product is greater than 15 on two rolls is (5/18)² = 25/324.
Answer:
0.03 is the probability that for the sample mean IQ score is greater than 103.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 100
Standard Deviation, σ = 16
Sample size, n = 100
We are given that the distribution of IQ score is a bell shaped distribution that is a normal distribution.
Formula:
Standard error due to sampling =

P( mean IQ score is greater than 103)
P(x > 103)
Calculation the value from standard normal z table, we have,

0.03 is the probability that for the sample mean IQ score is greater than 103.
The probability of drawing three jacks in a row from a standard deck of cards is, 3/4 or 3:4