<h2>
Answer:</h2>
The total number of handshakes that would happen between the three people are:
3
<h2>
Step-by-step explanation:</h2>
There are three people at a party.
Let they be denoted by A,B and C.
Now, the total number of handshakes that would occur will be denoted by:
AB, AC and BC
where AB denotes that A and B shake hands.
AC denote that A and C shake hands.
and BC denote that B and C shake hands.
Hence, total number of handshakes are:
3
3x + 15 = 66
<u> -15 -15</u>
3x = 51
Divide 51 by 3 which equals 17.
K=10
Here is the equation
180-115=65
(4K+5)+(6k+10)+65=180
Start with 180.
<span>Is 180 divisible by 2? Yes, so write "2" as one of the prime factors, and then work with the quotient, 90. </span>
<span>Is 90 divisible by 2? Yes, so write "2" (again) as another prime factor, then work with the quotient, 45. </span>
<span>Is 45 divisible by 2? No, so try a bigger divisor. </span>
<span>Is 45 divisible by 3? Yes, so write "3" as a prime factor, then work with the quotient, 15 </span>
<span>Is 15 divisible by 3? [Note: no need to revert to "2", because we've already divided out all the 2's] Yes, so write "3" (again) as a prime factor, then work with the quotient, 5. </span>
<span>Is 5 divisible by 3? No, so try a bigger divisor. </span>
Is 5 divisible by 4? No, so try a bigger divisor (actually, we know it can't be divisible by 4 becase it's not divisible by 2)
<span>Is 5 divisible by 5? Yes, so write "5" as a prime factor, then work with the quotient, 1 </span>
<span>Once you end up with a quotient of "1" you're done. </span>
<span>In this case, you should have written down, "2 * 2 * 3 * 3 * 5"</span>
