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3 years ago

9

Two cables were attached to the top of a pole and anchored to the ground on opposite sides of the pole. What is the length of th

e pole? Do not include units. Round to the nearest tenth of a foot.

1 answer:

poizon [28]3 years ago

7 0

This is a 16.2ft tall pole

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He values in the table represent a linear function. How does the value of y change in relation to a change in the value of x?

Ivahew [28]

Answer:

a

Step-by-step explanation:

because I have did this at school

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3 years ago

During a renovation project for the train station a parking lot for commuter train passengers is being enlarged. The original lo

snow_lady [41]

<span>86,400 yd^2. hope this helps :)</span>

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3 years ago

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A rectangle has a length that is 4 meters more than the width. The area of the rectangle is 117 square meters. Find the dimensio

pickupchik [31]

Answer:

Its the first choice. Width:9 Length:13

Step-by-step explanation:

If the length is 4 meter more than the width than that means whatever the width is you must add 4 to it, in this case the width is 9 so add 4 to it which equals 13. If the length matches your answer it is the correct choice.

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3 years ago

Write an equation for an ellipse centered at the origin, which has foci at (\pm\sqrt{8},0)(± 8 ,0)(, plus minus, square root o

Alchen [17]

Answer:

The equation of ellipse centered at the origin

$\frac{x^2}{18} +\frac{y^2}{10} =1$

Step-by-step explanation:

given the foci of ellipse (±√8,0) and c0-vertices are (0,±√10)

The foci are (-C,0) and (C ,0)

Given data (±√8,0)

the focus has x-coordinates so the focus is lie on x- axis.

The major axis also lie on x-axis

The minor axis lies on y-axis so c0-vertices are (0,±√10)

given focus C = ae = √8

Given co-vertices ( minor axis) (0,±b) = (0,±√10)

b= √10

The relation between the focus and semi major axes and semi minor axes are $c^2=a^2-b^2$

$a^{2} = c^{2} +b^{2}$

$a^{2} = (\sqrt{8} )^{2} +(\sqrt{10} )^{2}$

$a^{2} =18$

$a=\sqrt{18}$

The equation of ellipse formula

$\frac{x^2}{a^2} +\frac{y^2}{b^2} =1$

we know that $a=\sqrt{18} and b=\sqrt{10}$

<u>Final answer:</u>-

<u>The equation of ellipse centered at the origin</u>

<u /> $\frac{x^2}{18} +\frac{y^2}{10} =1$ <u />

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3 years ago

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Rus_ich [418]

Answer:

OA

Step-by-step explanation:

yax2;

12+34+5+6=21 so y2+35

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2 years ago